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 P: 1 Ok, so after expanding: ln(q+N)!-lnq!-lnN! and canceling a coupel N's and q's I get: (q+N)ln(q+N)-qlnq-NlnN So I applied a few ln rules to get: $$ln(q+N)^{q+N)}$$-$$lnq^{q}$$-$$Nln^{N}$$ Then simplifying: ln($$(q+N)^{(q+N)}/q^{q}$$-$$lnN^{N}$$ But when I try to simplify again I come up with: ln($$(q+N)^{(q+N)}N^{N}/q^{q}$$ - $$lnN^{N}$$ Which I don't believe is right, but even if it was, how do I go about recovering the 2pi n the denominator?