Thread: Partial Fractions View Single Post
 Mentor P: 18,231 Hi Deathfish! If your result is $$-\frac{x+4}{16x^2}+\frac{1}{16(x+4)}$$ then it is completely correct!! Now, why does mathematica give another result? Well, the above result can be put in a form that is even more convenient. Indeed, the term $\frac{x+4}{16x^2}$ can be "simplified" further as $$\frac{x+4}{16x^2}=\frac{1}{16x}+\frac{1}{4x^2}$$ This is a better form since it's more suitable for integration purposes. But your result isn't wrong!