Thread: Calculation of the integral View Single Post
P: 10
 Quote by JJacquelin In the function sigma(r), if you replace the exopential function (which tends to zero when r tends to infinity) by a linear function which tends to -infinity when r tends to infinity), indeed, the result will differ greatly. So greatly that the integral (from 0 to infinity) is no longer convergent.
What do I do?

The exponential law of density distribution $\sigma (r)) = \sigma_{0} \exp(-\frac{r}{L})$
I want to apply a linear truncation for $\sigma (r)$
$\sigma (r) = \left\{\begin{matrix}\sigma (r), &r < Rt \\ \sigma (Rt)(1+(Rt-r)/SCL), & Rt < r < Rt+SCL\\ 0, & r > Rt+SCL \end{matrix}\right.$