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Simple Integral but unknown method
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mathman
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Dec7-11, 03:49 PM
Sci Advisor
P: 6,039
R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)}
Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1