Thread
:
Simple Integral but unknown method
View Single Post
mathman
#
2
Dec7-11, 03:49 PM
Sci Advisor
P: 6,062
R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)}
Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1