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stardust006
#1
Feb28-12, 07:14 AM
P: 9
Find the area of the loop of the curve y^2=x^3(1-x)^2 using integral calculus.

y=√x^3(1-x)^2
y=√x^3/2 (1-x)


To sketch the curve, I assigned values for x and then solved the corresponding values of y.

x= -1, y= -2
x= -0.5, y= -0.53
x=0, y= 0
x= 0.5, y= 0.177
x=1, y=0

how can i find the area of this? >.<
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