Find the area of the loop of the curve y^2=x^3(1x)^2 using integral calculus.
y=√x^3(1x)^2
y=√x^3/2 (1x)
To sketch the curve, I assigned values for x and then solved the corresponding values of y.
x= 1, y= 2
x= 0.5, y= 0.53
x=0, y= 0
x= 0.5, y= 0.177
x=1, y=0
how can i find the area of this? >.<
