View Single Post
Mar8-12, 09:45 PM
P: 130
1. The problem statement, all variables and given/known data

Consider the superposition of two waves;

[itex]\zeta_1 + \zeta_2 = \zeta_{01} e^{i(kr_1 - wt)} + \zeta_{02} e^{i(kr_2 - wt + ∅)} [/itex]

where [itex] ∅ [/itex] is a phase difference that varies randomly with time. Show that the time-averages satisfy;

[itex]<|\zeta_1 + \zeta_2|^2> = <|\zeta_1|^2> + <|\zeta_2|^2> [/itex]

2. Relevant equations

(1) If it wasn't clear, The two waves are;

[itex] \zeta_1 = \zeta_{01} e^{i(kr_1 - wt)} [/itex] and
[itex]\zeta_2 = \zeta_{02} e^{i(kr_2 - wt + ∅)} [/itex]

3. The attempt at a solution

Unless I have my definition of time-average wrong. I can't seem to get this to work.

[itex]|\zeta_1 + \zeta_2|^2 = (\zeta_1 + \zeta_2)(\zeta_1^* + \zeta_2^*) = |\zeta_1|^2 + |\zeta_2|^2 + \zeta_1\zeta_2^* + \zeta_2\zeta_1^* = |\zeta_1|^2 + |\zeta_2|^2 + 2\zeta_{01}\zeta_{02}cos(k(r_1 - r_2) - ∅)[/itex]

Then, I believe, the time average is given by;

[itex]\frac{1}{T}\int^T_0 {|\zeta_1|^2 + |\zeta_2|^2 + 2\zeta_{01}\zeta_{02}cos(k(r_1 - r_2) - ∅)} dt[/itex]

However, I don't see how this turns in to the form I desire. It would require that the last term (containing the cosine) is time-averaged to zero. Can this be the case? Also, can [itex] ∅ [/itex] still even be considered a function of time when it varies RANDOMLY?
Phys.Org News Partner Science news on
Experts defend operational earthquake forecasting, counter critiques
EU urged to convert TV frequencies to mobile broadband
Sierra Nevada freshwater runoff could drop 26 percent by 2100