View Single Post
bold
bold is offline
#1
Mar27-05, 05:53 PM
P: 4
This is the last problem on a geometry problem set that I can't seem to finish.

AB and BC are chords in a circle where AB > BC. D is the midpoint of minor arc ADBC. If DE is perpendicular to AB, prove that AE = EB + BC.

I would really appreciate just the proper way to approach this question instead of a solution. I've tried joining CD and AC and using similar triangles but to no avail. I've also tried applying sine law on triangles ADE and DBC, no dice either.


Thanks in advance.
Phys.Org News Partner Science news on Phys.org
Going nuts? Turkey looks to pistachios to heat new eco-city
Space-tested fluid flow concept advances infectious disease diagnoses
SpaceX launches supplies to space station (Update)