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Ln x dxby PrudensOptimus
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#1
Jan404, 05:41 PM

P: 640

Integrat Ln[x]dx!!!!



#2
Jan404, 05:47 PM

P: 333

Consider it as 1*ln(x) and use parts.



#3
Jan404, 10:06 PM

P: 45

If you don't feel like doing it, you can always use:
The Integrator It gives the answer: [tex] x + x \ln x [/tex] 


#5
Jan504, 09:19 AM

P: 333

Hmm, didn't consider that. I'm not sure there'd be a closed form expression for [itex]\int ln[x] dx [/itex]
where [itex][x][/itex] is the next greatest integer function. It'd be easy enough to get a numerical answer if the interval was specified though. 


#6
Jan504, 10:24 AM

P: 22

You could break the integral into a summation. [x] is constant between intervals of integers, so you end up with a sum of trivial integrals.
I think this is what Lonewolf is proposing (please excuse my ignorance!) Regards, Sam 


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