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Does MWI Resolve Locality Problems with Entanglement? |
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| Dec28-07, 01:10 PM | #1 |
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Does MWI Resolve Locality Problems with Entanglement?
I believe I read that the Everett Many Worlds Interpretation resolves the apparent locality problems with entanglement (i.e. the necessity of a faster-than-light influence to explain the correlations between the behavior of entangled particles). If so I'm not sure how.
MWI says that the universe splits every time two quana interact, right? So for the entangled photons A and B, each time the two photons are sent through polarizers the universe splits four ways (AB, ab, aB, Ab). The universe splits four ways each time the experiment is run (n times), for a total of 4^n universes after the entire experiment is over. Assuming the Bell Inequality is still violated, depending on the polarizer settings (say 22.5 and 45 degrees), we know that the number of occurrences of AB, and ab will be grossly disproportionate to Ab and aB. Meaning, somehow, in the act of splitting the universes, bias was given toward both particles either passing or failing. Does this still not imply the same locality issues as any single-world interpretation would? |
| Dec29-07, 09:01 AM | #2 |
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Does it resolve “locality” problems? Only from within a WMI view of what “local” is. Until some WMI devised experiment is performed that conclusively demonstrates at least one of those other worlds actually exists, IMO the answer is NO. |
| Dec29-07, 07:16 PM | #3 |
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What I still don't understand is if the theory explains how the "splitting routine" is biased toward creating the appearance of our beloved Bell inequality violations without "knowing" the angles of the two polarizers. And how can any mechanism "know" the angles in the delayed choice experiments where the choice is made while the photon is mid-flight?
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| Dec31-07, 06:22 PM | #4 |
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Does MWI Resolve Locality Problems with Entanglement? |
| Dec31-07, 09:27 PM | #5 |
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If splitting would be local, then it get's interesting, I'd think, if at one location there is a split into a 1000 universes, and at another into 2000. So when the local "splitting waves" (or whatever that would be) meet each other, they suddenly multiply into 2 Million universes? If one believes in MWI, and one considers life worthwhile, is there a moral obligation to conduct as many quantum experiments as possible, in order to share the joy? Regarding the non-locality of Entanglement, the above quoted 'Everett Interpretation FAQ" is from 1995. However many decisive experiments regarding non-locality were performed 1998 and later, especially the GHZ experiments, which take non-locality out of the statistical correlation realm into that of definite predictions. [Edit added:] Nowadays it's a bit odd to just postulate that there should be a local explanation without being able to specify one that is at least plausible. (Also I've seen MWI listed as non-local in some overviews.) |
| Dec31-07, 09:59 PM | #6 |
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| Jan1-08, 12:05 AM | #7 |
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It seems obvious to me that MWI would have to postulate that such an experimenter "A" will be matched by a corresponding experimenter "B". However it seems equally obvious, that if "A" and "B" are spacelike separate, that then this would imply the splitting process to be non-local, contrary to the postulate that splitting is assumed (or defined) to be local. And this is where the experiments from 1998 and later come in, as they ensure the spacelike separation of "A" and "B". [Edit added:]On re-reading this I find it again necessary to point out that the result at "B" is impacted by the measurement angles at "A", not just in correlation with the result of "A". That is, there is a spacelike separate effect of action at "A" on results at "B". Only talking about correlations too easily creates the impression that the results could simply be in a corresponding sequence, independent of any actions at the other location. |
| Jan1-08, 12:29 AM | #8 |
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If you don't have collapse, then the following is true in LQFT:
(1) Space-time has a causal structure. This is the familiar structure given to us by Special Relativity. (2) We can restrict states. If R is a region of space-time, then we can consider the restriction of the state of the universe to R. If S is a subregion of R, then we can further restrict the state to S, etc. (i.e. if we know everything about the universe, we know everything about Alice's lab. And if we know that, then we can describe any experiment that takes place in part of her lab) (3) The state of the universe is non-local. If the region R consists of two regions S and T, then knowledge of the state restricted to S and the state restricted to T is insufficient to recover the state in R. (i.e. if you know everything about Alice's lab and you know everything about Bob's lab, that isn't sufficient to fully describe any experiment that involves both labs) (4) The evolution of the state is local. If a region R is causally determined by some other region S, and we know the state of the universe restricted to S, that is enough to determine the state restricted to R. (i.e. if we know everything about an instantaneous region of space one light-year in diameter about the Earth, we can then fully describe any experiment that happens on Earth for the next year) |
| Jan1-08, 07:12 AM | #9 |
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| Jan1-08, 08:12 AM | #10 |
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The answer to the first question is that the results of B do depend on the measurement angles at A, in their relation to the angles at B. That is, how A and B correlate depends on the relative angles at A and B. In other words, results at B correlate not just with the results at A, but with the combination of the results at A and the relative measurement angles at A and B. If there is a third observer exactly in the middle "M", between A and B, and if A and B immediately send signals about the measurement result, then the universe (unless it has non-local intelligence) has no means of instantly pairing up the correct sub-universes, as it depends on the measurement angles how they will need to be paired up (especially in the GHZ case of more than two entangled particles). That is, there would need to be an intelligent process, yet no time for such a process. I hope this response reflects an adequate interpretation of this concept of "pairing up", of which I don't know more than you have written. |
| Jan1-08, 10:47 AM | #11 |
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Let's look at the simple case of two-particle entanglement. Suppose Bob and Alice are each receiving one member of an entangled pair, and each has three measurement settings A, B, and C, and the particles are entangled in such a way that they are always guaranteed to get opposite results if they pick the same measurement setting--if Bob picks setting A and gets result +1 then if Alice also picks setting A, she's guaranteed to get result -1. As I explained in post #5 of this thread, in this situation local realism predicts that when they pick different settings, they should get opposite results on at least 1/3 of all trials; but with the right choice of measurement angles it is possible to ensure that they actually get opposite results less frequently, say on only 1/4 of all trials, which is a violation of Bell's theorem. But now look at this in a situation where we allow multiple copies of each experimenter. For concreteness, let's say we have A.I. experimenters doing a simulated version of this experiment on computers at different locations, and we want to reproduce this apparent violation of Bell's theorem in a purely classical way, just by running multiple copies of each A.I. experimenter on each computer. Now suppose on a given trial the Bob-A.I. picks a particular setting, say C, and the computer has to decide how to split Bob into copies who observe different results before it gets a message from the other computer about what setting the Alice-A.I. chose. All it needs to do is split Bob into 8 copies with the following results: 1. Bob measures A, gets +1 2. Bob measures A, gets +1 3. Bob measures A, gets +1 4. Bob measures A, gets +1 5. Bob measures A, gets -1 6. Bob measures A, gets -1 7. Bob measures A, gets -1 8. Bob measures A, gets -1 Now sometime later, a group of signals from all the Alice-copies comes from the other computer, and the computer simulating Bob has to decide which Alice-copy-signal is received by each Bob-copy. Suppose it turns out that Alice had also chose setting A, and the computer simulating her had split her into 8 copies in the same way: 1. Alice measures A, gets +1 2. Alice measures A, gets +1 3. Alice measures A, gets +1 4. Alice measures A, gets +1 5. Alice measures A, gets -1 6. Alice measures A, gets -1 7. Alice measures A, gets -1 8. Alice measures A, gets -1 In this case the computer simulating Bob can match up signals like this: Bob 1 gets signal from Alice 5 (Bob +1, Alice -1) Bob 2 gets signal from Alice 6 (Bob +1, Alice -1) Bob 3 gets signal from Alice 7 (Bob +1, Alice -1) Bob 4 gets signal from Alice 8 (Bob +1, Alice -1) Bob 5 gets signal from Alice 1 (Bob -1, Alice +1) Bob 6 gets signal from Alice 2 (Bob -1, Alice +1) Bob 7 gets signal from Alice 3 (Bob -1, Alice +1) Bob 8 gets signal from Alice 4 (Bob -1, Alice +1) This will guarantee that each Bob finds that Alice got the opposite result from his own. On the other hand, suppose it turns out that Alice had chose setting C, and her computer had split her up like this: 1. Alice measures C, gets +1 2. Alice measures C, gets +1 3. Alice measures C, gets +1 4. Alice measures C, gets +1 5. Alice measures C, gets -1 6. Alice measures C, gets -1 7. Alice measures C, gets -1 8. Alice measures C, gets -1 In this case, the computer simulating Bob could match the signals like so: Bob 1 gets signal from Alice 1 (Bob +1, Alice +1) Bob 2 gets signal from Alice 2 (Bob +1, Alice +1) Bob 3 gets signal from Alice 3 (Bob +1, Alice +1) Bob 4 gets signal from Alice 5 (Bob +1, Alice -1) Bob 5 gets signal from Alice 4 (Bob -1, Alice +1) Bob 6 gets signal from Alice 6 (Bob -1, Alice -1) Bob 7 gets signal from Alice 7 (Bob -1, Alice -1) Bob 8 gets signal from Alice 8 (Bob -1, Alice -1) In this case 6/8 of the Bob-copies find that Alice got the same result as their own, while only 2/8 = 1/4 find that Alice got the opposite result. If Bob and Alice don't realize they are living in computer simulations and have been split into multiple copies, they will think that their results violate Bell's theorem. You could certainly have a third computer midway between the ones simulating Alice and Bob, simulating a third observer, "Marvin". Then if Alice and Bob each send their results to Marvin, and there are 8 copies of Marvin as well, you could match them up like so: Marvin 1 gets signals from Bob 1 and Alice 1 (Bob +1, Alice +1) Marvin 2 gets signals from Bob 2 and Alice 2 (Bob +1, Alice +1) Marvin 3 gets signals from Bob 3 and Alice 3 (Bob +1, Alice +1) Marvin 4 gets signals from Bob 4 and Alice 5 (Bob +1, Alice -1) Marvin 5 gets signals from Bob 5 and Alice 4 (Bob -1, Alice +1) Marvin 6 gets signals from Bob 6 and Alice 6 (Bob -1, Alice -1) Marvin 7 gets signals from Bob 7 and Alice 7 (Bob -1, Alice -1) Marvin 8 gets signals from Bob 8 and Alice 8 (Bob -1, Alice -1) But there's no need for the computers simulating Alice and Bob to know which copy of Alice is paired up with which copy of Bob at the same instant--for example, Bob's computer doesn't have to decide this until a simulated message from Alice has had time to arrive there, or a simulated message from Marvin sent after he had received a message from Alice (if both messages were sent as quickly as possible they would reach Bob at the same moment). So, we can still simulate all the aspects of this situation that are predicted by QM perfectly well using classical computers that create multiple copies of each observer, with the actual signals between computers not able to travel any faster than the simulated messages between observers in the simulated universe. |
| Jan1-08, 12:09 PM | #12 |
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First, I think that moving the whole scenario onto a computer simulation doesn't help your case, since on a computer, space is simulated and so there is no 'locality' in the first place. Or maybe I missed the point there. A computer (even a classical one, I guess) could simulate anything it wants to simulate, and we are still left with the task to figure out what is going on "inside the simulation". So I think we should put that aside as distracting. Your description skips the part where the "computer" needs to match up the sub-universes, and how it does that. It does seem to indeed require logic, which in turn requires time, which in turn isn't available (for example when the signals are sent immediately and meet in the middle, and are recorded there). Also, in reality there is no computer available to perform this "matching up", it would have to be a physical process that can take place with any kind of signal that could be recorded in the middle, so I'd say with two photons meeting in the middle. How are two photons going to figure that out? Even if you were to construct some kind of undercover avalanche of "universe-internal" information that gets sent along "automatically", then you will still run into an unsolvable problem (I think) when one extends the experiment to a large triangle with A, B and C at the corners and three additional observers at each middle point (AB, BC, AC). Then the three sub-universes must be matched up when the signals meet at these middle points AB, BC and AC. But if there is no FTL at all (or rather: no non-locality), then at this point in time, at each middle point, there can be only information about two of the three angles, and I'd guess this information wouldn't be sufficient. An additional limiting factor here is, that now the matching up has to be consistent, that is, the meeting points AB and AC must make the same choice about which A sub-universe to pick, otherwise there will be a contradiction (when BC has already been established, so to speak). As presented so far, I don't think this is a viable scenario, for multiple reasons. |
| Jan1-08, 01:00 PM | #13 |
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| Jan1-08, 01:39 PM | #14 |
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Even if you were to construct some kind of undercover avalanche of "universe-internal" information that gets sent along "automatically", then you will still run into an unsolvable problem (I think) when one extends the experiment to a large triangle with A, B and C at the corners and three additional observers at each middle point (AB, BC, AC). Then the three sub-universes must be matched up when the signals meet at these middle points AB, BC and AC. But if there is no FTL at all (or rather: no non-locality), then at this point in time, at each middle point, there can be only information about two of the three angles, and I'd guess this information wouldn't be sufficient. An additional limiting factor here is, that now the matching up has to be consistent, that is, the meeting points AB and AC must make the same choice about which A sub-universe to pick, otherwise there will be a contradiction (when BC has already been established, so to speak). |
| Jan1-08, 01:52 PM | #15 |
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| Jan1-08, 07:56 PM | #16 |
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Let's say when signals meet at AB, that A5 is matched with B2. When signals meet at AC, A5 is matched with C3. This already implies that at BC, the copies of systems B and C that need to be matched up include the pair B2 and C3. So at this point, the mapping (A5,B2,C3) is already fixed, even though there is no "common point in space" that has been reached by "signals from all three measurements". Since there is no upper limit for the number of entangled particles, this can be extended arbitrarily. You might have a large ring of a 100 systems, where at each midpoint the available information is only 2 out of 100 angles and results, and still the copies of all 100 systems must be matched up. |
| Jan1-08, 08:39 PM | #17 |
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So as long as we do not assign specific names to copies beyond the physical aspects of their history that differentiate them, and the "mapping" amounts to no more than a statement that a copy A who gets a signal from a copy B with a certain history is marked in this way and will continue to only receive signals from copies of B with that same history, I don't think we will have the type of problem you mention above. But again, if you disagree perhaps it would be a good idea to try to apply all this to a specific example like the GHZ experiment. |
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