Equation that predicts quark masses

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Discussion Overview

The discussion revolves around a proposed equation that claims to predict the rest masses of quarks, including two hypothetical quarks, X1 and X2. Participants explore the implications of this equation, its derivation, and its relationship to known particle masses, particularly in the context of the standard model of particle physics.

Discussion Character

  • Exploratory
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents an equation that predicts quark masses based on a relationship involving electric charge and an integer parameter n, asserting its validity and intent to submit it for publication.
  • Another participant critiques the equation, suggesting it relies on unjustified parameters and questions the methodology behind the mass predictions.
  • A participant claims to find a ratio involving the masses of quarks that corresponds to the ratio of the muon to the electron mass, raising questions about the validity of the initial claims.
  • There is a challenge regarding the empirical nature of the proposed equation, with one participant accusing another of manipulating data to achieve desired results.
  • Another participant expresses skepticism about the method used to derive the coefficients in the proposed mass table, suggesting it may not be as groundbreaking as claimed.
  • A separate contribution introduces a different equation aimed at predicting lepton masses, indicating a broader interest in mass prediction formulas within the thread.

Areas of Agreement / Disagreement

Participants express a range of opinions, with some supporting the proposed equation and others challenging its validity and methodology. There is no consensus on the correctness of the claims made regarding quark masses or the relationship to lepton masses.

Contextual Notes

Participants note the uncertainty in quark mass values and the potential influence of empirical data on the proposed equation. The discussion highlights the complexity of deriving mass predictions and the challenges in justifying parameters used in such equations.

kurious
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The standard model can't predict the rest masses of all known and unknown particles - something is missing from it.I have found an equation by trial and error that predicts all quark masses:




EQUATION THAT PREDICTS QUARK REST MASSES

The following equation generates the masses, in Gev, associated with the six quarks:
Down, up, strange, charm, bottom, top and predicts the masses of two new quarks labelled X1 and X2.


M = 12.50 x 10 3pi (n – 5) / 2 0 x ( n – 4 ) 2 x 10 39 ( n – 3 ) / 2 x 10 57 x q n (5)

M = f (n) q n

Where n is an odd numbered integer and q is the magnitude of the electric charge associated with the mass. The equation was based on the idea that
mass = constant x q n and that the constant depends on n and is different for each quark pair - the pairs are next to each other in the table.



QUARK CHARGE n MASS (Gev) )

DOWN - 1/3 -1 0.0088

UP + 2/3 -1 0.0044

X1 -1/3 +1 0.084

X2 +2/3 +1 0.16

STRANGE -1/3 +3 0.21

CHARM +2/3 +3 1.72

BOTTOM -1/3 +5 5.20

TOP +2/3 +5 167.25

I now understand why this equation works and I am going to submit it to a journal later in the year.The quark at n = +1 doesn't actually exist because of the colour force.This equation enables the rest mass of the muon to be predicted accurately too! The constant k changes for each quark family.
 
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Ok you have a phenomenological mass formula with some (a lot!) unjustified parameters. No big deal.
 
When I take two up quarks from my equation and add their rest masses to a down quark ( constituents of a normal proton), and compare this to the total mass my equation predicts for a proton made from two charm quarks and a strange quark, I get the ratio of the mass of the muon to that of the electron.I only noticed this after I had settled on what the quark masses should be.
 
Mmm are you telling that
[tex]{2 m_c + m_s \over 2 m_u + m_d} = {m_\mu \over m_e}[/tex]
?
I see, yep, 207 both sides.
 
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kurious said:
I only noticed this after I had settled on what the quark masses should be.
Well, the simple answer is that you are most probably a lier.

I will refer the unaware public to the table http://pdg.lbl.gov/2002/qxxx.pdf
where the uncertainty in masses is clearly stated. You have choosen the quotient muon/electron as a hidden input in your empirical table and then waited one day to claim the "discovery".

Otherwise, please explain the method to find the coefficients in your table and I will apologise.
 
arivero said:
Mmm are you telling that
[tex]{2 m_c + m_s \over 2 m_u + m_d} = {m_\mu \over m_e}[/tex]
?
I see, yep, 207 both sides.

Yes, but what does that matter? It is not like the the leptons are made of quarks...
 
tex formulas...

M = 12.50 x 10 3pi (n ? 5) / 2 0 x ( n ? 4 ) 2 x 10 39 ( n ? 3 ) / 2 x 10 57 x q n (5)

M = f (n) q n


Can someone please re-write this equation in TEX format?

The currently stated equation is still extremely vague, and do not want to spend time guessing as to its proper mathematical orientation.

[/color]
 
Orion, I believe the key is in the text:
kurious said:
q is the magnitude of the electric charge associated with the mass.
How is this magnitude, generation dependent, introduced? I guess that kurious used the quotient between leptonic masses as a way to "define" these magnitudes; in this way it is not strange it gets it as an output with 0.1% precision.

Of course, if the method does not involve this quotient, kurious had got a remarkable, better, REMARKABLE, result. I am afraid it is not so, as he has backed from this thread.
 
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Lepton Lesson...



I developed an equation that predicts the lepton masses in Mev along the x-axis intercept: (x = Lepton mass (Mev) when [tex]\Psi(x) = 0[/tex])

[tex]\Psi(x) = x(x^2 - xE_1 + E_2^2) - E_3^3[/tex]
[tex]\Psi(x)[/tex] - function amplitude (Mev^3)
x - energy spectrum (Mev)
E1 = 1677.789 Mev
E2 = 435.355 Mev
E3 = 45.845 Mev

I will demonstrate how this was accomplished later in thread, however, calculus students should be able to recognize how this formula was compiled as well as demonstrate my point.

 
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