Why Is the Electric Displacement Field Important in Understanding Capacitors?

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SUMMARY

The electric displacement field (D) is crucial for understanding capacitors, particularly in the context of displacement current. When a capacitor charges or discharges, a displacement current flows, which preserves Kirchhoff's first rule by accounting for the current in the external circuit while no current flows through the dielectric. The relationship is defined by the equation I = C(dV/dt), where I represents the displacement current, C is the capacitance, and dV/dt is the rate of voltage change. This concept is integral to the Ampère-Maxwell law, demonstrating the importance of the electric displacement field in circuit analysis.

PREREQUISITES
  • Understanding of capacitors and their operation
  • Familiarity with Kirchhoff's laws
  • Basic knowledge of Maxwell's equations
  • Concept of displacement current in electromagnetism
NEXT STEPS
  • Study the derivation and implications of the Ampère-Maxwell law
  • Explore the concept of displacement current in more detail
  • Investigate the role of electric displacement field in dielectric materials
  • Learn about the practical applications of capacitors in electronic circuits
USEFUL FOR

Electrical engineers, physics students, and anyone interested in the theoretical and practical aspects of capacitors and electromagnetic fields.

Vanush
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Can someone please post a problem/situation outlining the motivation / usefulness of the electric displacement field? (Particularly with a capacitor) I'm having trouble understanding the concept and information is sparse on the internet.
 
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Vanush said:
Can someone please post a problem/situation outlining the motivation / usefulness of the electric displacement field? (Particularly with a capacitor) I'm having trouble understanding the concept and information is sparse on the internet.

Hi Vanush! :smile:

For electric displacement field in a capacitor, this (from the PF Library) may help:

Displacement current:

No current ever flows through a functioning capacitor.

But while a capacitor is charging or discharging (that is, neither at zero nor maximum charge), current is flowing round the circuit joining the plates externally, and so there would be a breach of Kirchhoff's first rule (current in = current out at any point) at each plate, if only ordinary current were used, since there is ordinary current in the circuit on one side of the plate, but not in the dielectric on the other side.

Accordingly, a displacement current is deemed to flow through the capacitor, restoring the validity of Kirchhoff's first rule:

[tex]I\ =\ C\frac{dV}{dt}[/tex]

and this linear displacement current [itex]I[/itex] (which might better be called the flux current or free flux current) is the rate of change of the flux (field strength times area) of the electric displacement field [itex]D[/itex]:

[tex]I\ =\ A\,\widehat{\bold{n}}\cdot\frac{\partial\bold{D}}{\partial t}\ =\ A\,\frac{\partial D}{\partial t}\ =\ C\frac{dV}{dt}[/tex]

which appears in the Ampére-Maxwell law (one of Maxwell's equations in the free version):

[tex]\nabla\,\times\,\bold{H}\ =\ \bold{J}_f\ +\ \frac{\partial\bold{D}}{\partial t}[/tex]

Note that the displacement alluded to in the displacement current across a capacitor is of free charge, and is non-local, since it alludes to charge being displaced from one plate to the other, which is a substantial distance compared with the local displacement of bound charge in, for example, the presence of a polarisation field.
 

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