May20-04, 07:50 PM
well here is the question:
Manganese Dioxide, MnO2, was fused with Sodium Hydroxide, NaOH, and an oxidising agent potassium chlorate(v), KCLO3. The result was a green solid containing K2MnO4, and potassium chloride, KCL. This mixture was powdered and boiled with water through which carbon dioxide was bubbled for a while. The mixture was then filtered to remove MnO2, and the purple filtrate was carefully evaporated.
In the synthesis above, write the complete ionic equations showing the formation of:
I put an astrate before the charge so whatever comes after the astrate is the charge on the molecule. And, one more thing, Is the CO2 there just to create an acidic condition.
Here's a little added info.
In standard acid conditions
2MnO4*-(aq) + 2e*- <--> 2MnO4*2-
MnO4*2- (aq)+ 4H*+ + 2e-<--> MnO2(S) + 2H2O(l)
In standard alkaline conditions
2MnO4*-(aq) + 2e*-<-->2MnO4*2-
MnO4*2- (aq)+ 2H2O(l) + 2e-<--> MnO2(S) + 4OH*-
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