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Current in a solution 
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#1
Apr1009, 07:53 PM

P: 2

I don't even know what equation to use!
In an ionic solution, 5.0*10^15 positive ions with +2e charge pass to the right each second while 6.0*10^15 negative ions with charge e pass to the left. What is the magnitude of current in the solution? (5.0*10^15)*(2*1.6*10^19)  (6.0*10^15)*(1.6*10^19)=8.3*10^4 


#2
Apr1009, 07:57 PM

HW Helper
P: 4,439

Check the calculation.



#3
Apr1009, 08:03 PM

P: 2

my calculation was wrong, when I recalculated it i got 6.4E4, and that was still wrong
What equation should i use? 


#4
Apr1009, 08:24 PM

HW Helper
P: 4,439

Current in a solution
There must be two different solutions in the electrolyte. So when +2e charge from one solution moving toward right,2e charge is moving towards left. This adds to e charge from the second solution. So net flow of charge is 3e towards left.



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