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Trying to Understand Bell's reasoning |
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| May2-10, 12:31 AM | #18 |
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Trying to Understand Bell's reasoningThat's because your version of H is too vague and doesn't actually specify whether the red card was the one that was picked to send to Alice and the white card was the one that was picked to send to Bob, or vice versa. If you completely specified the hidden properties of the envelope that was sent to Alice--namely "the person who picked the cards from the box put the red card in Alice's envelope, and the envelope continued to have that hidden card on its journey to Alice"--then in that case it would be true that P(A|H)=P(A|BH). Perhaps you could take a look at the scratch lotto analogy I came up with a while ago and see if it makes sense to you (note that it's explicitly based on considering how the 'hidden fruits' might be distributed if they were known by a hypothetical observer for whom they aren't 'hidden'): Suppose we have a machine that generates pairs of scratch lotto cards, each of which has three boxes that, when scratched, can reveal either a cherry or a lemon. We give one card to Alice and one to Bob, and each scratches only one of the three boxes. When we repeat this many times, we find that whenever they both pick the same box to scratch, they always get the same result--if Bob scratches box A and finds a cherry, and Alice scratches box A on her card, she's guaranteed to find a cherry too. Classically, we might explain this by supposing that there is definitely either a cherry or a lemon in each box, even though we don't reveal it until we scratch it, and that the machine prints pairs of cards in such a way that the "hidden" fruit in a given box of one card always matches the hidden fruit in the same box of the other card. If we represent cherries as + and lemons as -, so that a B+ card would represent one where box B's hidden fruit is a cherry, then the classical assumption is that each card's +'s and -'s are the same as the other--if the first card was created with hidden fruits A+,B+,C-, then the other card must also have been created with the hidden fruits A+,B+,C-. The problem is that if this were true, it would force you to the conclusion that on those trials where Alice and Bob picked different boxes to scratch, they should find the same fruit on at least 1/3 of the trials. For example, if we imagine Bob and Alice's cards each have the hidden fruits A+,B-,C+, then we can look at each possible way that Alice and Bob can randomly choose different boxes to scratch, and what the results would be: Bob picks A, Alice picks B: opposite results (Bob gets a cherry, Alice gets a lemon) Bob picks A, Alice picks C: same results (Bob gets a cherry, Alice gets a cherry) Bob picks B, Alice picks A: opposite results (Bob gets a lemon, Alice gets a cherry) Bob picks B, Alice picks C: opposite results (Bob gets a lemon, Alice gets a cherry) Bob picks C, Alice picks A: same results (Bob gets a cherry, Alice gets a cherry) Bob picks C, Alice picks picks B: opposite results (Bob gets a cherry, Alice gets a lemon) In this case, you can see that in 1/3 of trials where they pick different boxes, they should get the same results. You'd get the same answer if you assumed any other preexisting state where there are two fruits of one type and one of the other, like A+,B+,C- or A+,B-,C-. On the other hand, if you assume a state where each card has the same fruit behind all three boxes, so either they're both getting A+,B+,C+ or they're both getting A-,B-,C-, then of course even if Alice and Bob pick different boxes to scratch they're guaranteed to get the same fruits with probability 1. So if you imagine that when multiple pairs of cards are generated by the machine, some fraction of pairs are created in inhomogoneous preexisting states like A+,B-,C- while other pairs are created in homogoneous preexisting states like A+,B+,C+, then the probability of getting the same fruits when you scratch different boxes should be somewhere between 1/3 and 1. 1/3 is the lower bound, though--even if 100% of all the pairs were created in inhomogoneous preexisting states, it wouldn't make sense for you to get the same answers in less than 1/3 of trials where you scratch different boxes, provided you assume that each card has such a preexisting state with "hidden fruits" in each box. But now suppose Alice and Bob look at all the trials where they picked different boxes, and found that they only got the same fruits 1/4 of the time! That would be the violation of Bell's inequality, and something equivalent actually can happen when you measure the spin of entangled photons along one of three different possible axes. So in this example, it seems we can't resolve the mystery by just assuming the machine creates two cards with definite "hidden fruits" behind each box, such that the two cards always have the same fruits in a given box. And you can modify this example to show some different Bell inequalities, see post #8 of this thread for one example. For example, suppose we have two identical-looking flashlights X and Y that have been altered with internal mechanisms that make it a probabilistic matter whether they will turn on when the switch is pressed. The mechanism in flashlight X makes it so that there is a 70% chance it'll turn on when the switch is pressed; the mechanism in flashlight Y makes it so there's a 40% chance when the switch is pressed. The mechanism's random decisions aren't affected by anything outside the flashlight, so whether or not flashlight X turns on doesn't change the probability that flashlight Y turns on. Now suppose we do an experiment where Alice is sent one flashlight and Bob is sent the other, by a sender who has a 50% chance of sending X to Alice and Y to Bob, and a 50% chance of sending Y to Alice and X to Bob. Let H1 and H2 represent these two possible sets of "hidden" facts (hidden to Alice and Bob since the flashlights look identical from the outside): H1 represents the event "X to Alice, Y to Bob" and H2 represents the event "Y to Alice, X to Bob". Let A represent the event Alice's flashlight turns on when she presses the switch, B represents the event that Bob's flashlight turns on when she presses the switch. Here, P(A) = P(A|H1)*P(H1) + P(A|H2)*P(H2) = (0.7)*(0.5) + (0.4)*(0.5) = 0.55 and P(B) = P(B|H1)*P(H1) + P(B|H2)*P(H2) = (0.4)*(0.5) + (0.7)*(0.5) = 0.55 Since P(A|B) = P(A and B)/P(B), we must have P(A|B) = (0.7)*(0.4)/(0.55) = 0.5090909... So you see that P(A|B) is slightly lower than P(A), which makes sense since if Bob's flashlight lights up, that makes it more likely Bob got flashlight X which had a higher probability of lighting, and more likely A got flashlight Y with a lower probability of lighting. But despite the fact that B does give some information about the probability of A, it is still true that P(A|B and H1) = P(A|H1) = 0.7, since H1 tells us that Alice got flashlight X, and that alone completely determines the probability that Alice's flashlight lights up when she presses the switch, the fact that Bob's flashlight lit up won't alter our estimate of the probability that Alice's lights up. Likewise, P(A|B and H2) = P(A|H2) = 0.4. I'm sure that whatever the reference you gave says, it doesn't imply that this reasoning is incorrect. |
| May2-10, 08:40 AM | #19 |
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What is *your* answer? It would be helpful to get a straight answer. If you don't like the question, Bell is not likely to mean much to you - since this is the keystone to the paper. |
| May2-10, 10:22 AM | #20 |
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The question is not whether "outcomes pre-exist measurement". As I have explained already, there are many real locally causal situations in which outcomes do not pre-exist the act of measurement. Why are you so bent in insisting that this is the issue. I don't see that question/definition in the EPR paper at all. Maybe I missed it. Could you point me to where EPR says "outcomes must pre-exist measurement"? |
| May2-10, 10:42 AM | #21 |
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"In the absence of connections between the detectors and the source, a particle has no information about how the switch of its detector will be set until it arrives there. Since in each run any detector might turn out to be either the one set to 1 or one of the ones set to 2, to preserve the perfect record of always having an odd number of R flashes in 122, 212, and 221 runs, it would seem to be essential for each particle to be carrying instructions for how its detector should flash for either of the two possible switch settings in might find upon arrival." left hand column, p 732. "If the instruction sets existed, then 111 runs would always have to produce an odd number of R flashes. But they never do, as I remarked in the third paragraph of this section, ... . Thus, a single 111 run suffices all by itself to give data inconsistent with the otherwise compelling inference of instruction sets." right hand column, p 732. "Instruction sets require an odd number of R flashes in every 111 run; quantum mechanics prohibits an odd number of R flashes in every 111 run." left hand column, p 733. |
| May2-10, 10:43 AM | #22 |
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In any case, this is going off my main issue which I explained in my last post as follows: Note that if we assume that your reasoning is correct, the full equation P(AB|H) = P(A|H)P(A|BH) still works. But in Bell's case, using the full chain rule does not work. So there must be another justification for insisting on P(AB|H) = P(A|H)P(A|H) other than the one you have given. The justification for reducing P(A|BH) to P(A|H) is not based on whether B gives additional information but on whether B gives any information. (see Conditional Independence in Statistical Theory, J.R Statist. Soc B, 1979 41, No. 1, pp. 1-31) http://people.csail.mit.edu/tdanford...s/dawid-79.pdf if A and B are equal, numerically P(A|BH) = P(A|H), but you could not say in this situation that since B gives you no additional information to H, therefore A and B are independent. They clearly are dependent. Therefore, although it is correct to reduce P(A|H)P(B|AH) to P(A|H)P(B|H) as a result of conditional independence between A and B, it is not correct to go from the fact that their numerical values are the same, to say that they are conditionally independent. X implies Y does not necessarily mean Y implies X. See the paper above. Link added. Your other example does not address these points. |
| May2-10, 10:43 AM | #23 |
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| May2-10, 11:27 AM | #24 |
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If you don't even understand what a local hidden variables theory is, you really need to go back to basics and try to learn something about the ideas behind the proof, rather than rush to critique it before you even have the first idea of what it's saying. P(A) = 0.55 P(A|B) = 0.50909... P(A|H1) = 0.7 P(A|H1 and B) = 0.7 |
| May2-10, 02:00 PM | #25 |
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Don't get too discouraged Bill, there is always an opposition. Think of it as a test of your argument, not a personal attack. Now, I have not studied probability theory or local/nonlocal stuff much, so I am in no position to comment on that, but I can see that there are a lot of posts that aren't addressing his concern. I think there needs to be a well-defined list of axioms laid out for all to use in this argument. It would help a lot. Again, Bill's problem is with [2], not the outcome of Bell's stuff. He agrees that if [2] is true then the other stuff is all true, but the question is all about [2], not about the stuff that follows it. I don't think he is getting lost amongst the trees, I think he is questioning whether one of the trees in the forest really is a tree.
Edit: JesseM points out in the next post that what I really meant was [1] everywhere there is a [2] above, which is true. |
| May2-10, 02:22 PM | #26 |
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| May2-10, 06:18 PM | #27 |
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If you don't get this concept, you are missing the forest. It's cute you pretend that someone is the "loyal opposition" but actually Bill is coming off more as as a craggly contrarian. I am not actually sure craggly is a word, by the way. The meaning of Bell is what is important.
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| May2-10, 06:32 PM | #28 |
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billschnieder, I think DrChinese, JesseM and RUTA did a good job in trying to explain, but you still seem a little 'skeptical'.
The real problem is that you are making an assumption on completely wrong premises, almost like – "I can prove that the probability for this car making 100 mph doesn’t make sense" – when the car is actually making 200 mph... And I show you where your assumption goes wrong: This is called spin and superposition, and is absolutely fundamental in QM. Bell of course knew this when writing his ansatz. David Mermin's EPR gedanken experiment animated ![]() ...and you see why this is also wrong... |
| May2-10, 06:34 PM | #29 |
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| May2-10, 08:41 PM | #30 |
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Obviously you are opposing each other so there is no one distinct opposition, you are his opposition, he is yours... I was merely encouraging him to lay it out in detail, I don't have a horse in this race. Most of the arguments of this type (on these forums) end up with people bickering over little details about undefined objects. Define everything from the top, then argue.
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| May2-10, 09:09 PM | #31 |
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| May3-10, 10:59 AM | #32 |
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JesseM:
I definitely understand what EPR meant by "elements of reality", and I definitely understand that it DOES NOT mean "I can see the moon when I am not looking at it", which is implied if you say outcomes must pre-exist observation. In any case, this is a rabbit trail and distracts from the main issue which I have already explained. I am only interested in understand Bell's justification for writing P(AB|H) = P(A|H) * P(B|H) instead of P(AB|H) = P(A|H) * P(B|AH) In all your numerous examples and arguments, the only response relevant to this issue is your claim that, if H is completely specified, A adds no additional information to that already provided by H, therefore P(B|AH) = P(B|H). I don't have to respond to everything else in your rather verbose posts since this is the only point that is relevant to my issue. My response to this point, as I have already pointed out is as follows: 1) The definition of conditional independence is not based on additional information but on any information. In the article I quoted to you, section 2.1 titled "Definitions", page 2, midway down the page, where independence is defined it says: 2) If P(B|AH) is really equal to P(B|H) as you insinuate, then it shouldn't matter which equation is used. Both should result in the same inequalities right? Do you agree that it should be possible to derive Bell's inequalties from either equation? Now following Bell's logic, try to derive the inequalities from P(AB|H) = P(A|H) * P(B|AH). It can not be done! Can you explain to me why? Just to be clear that you understand this point, let me rephrase it -- P(B|AH) = P(B|H) and P(B|AH) [tex]\neq[/tex] P(B|H) can not both be true at the same time right? |
| May3-10, 12:13 PM | #33 |
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Do you understand what a "past light cone" is, and why it's essential to the definition of locality? In general, please don't just assume you know where I am going with a particular line of argument and then say dismissive things like "I don't have to respond to everything else in your rather verbose posts since this is the only point that is relevant to my issue". Consider the possibility that you may not actually understand everything about this issue, and therefore there may be points that you are missing. The alternative, I suppose, is that you have no doubt that you already know everything there is to know about the issue, and are already totally confident that your argument is correct and that Bell was wrong to write that equation, and are just here to pick a fight with Bell's defenders rather than to try to learn anything. If that's your attitude then this isn't really the forum for you--the IMPORTANT! Read before posting sticky in the relativity forum applies to the QM forum too: Are you familiar with the phrase "correlation is not causation"? We might find in some study that two variables A and B, such as sugar consumption and heart disease, are correlated--they are not conditionally independent. It might nevertheless be true that this is not because sugar consumption has any causal influence on heart disease, but rather because high sugar consumption tends to be correlated with some other factor C, like a diet with too much salt, that does have a causal influence on heart disease. In this case we would have a conditional dependence between sugar and heart disease, but no causal influence of sugar consumption on heart disease. Similarly, in the lotto card example, there is definitely a conditional dependence between the probability that Alice finds a cherry when she scratches box 1 of her card, and the probability that Bob finds a cherry when he scratches box 1 of his card--in fact, if the first is true, then we know the second is true with probability 1! But this isn't because Alice's scratching box 1 and finding a cherry had any causal influence on Bob's card. Rather it's because of an event in the past light cone of both these other two events, which exerted a causal influence on both--namely the source picking two lotto cards with an identical pattern of "hidden fruits" behind the respective boxes on each card, with the hidden fruits associated with each card staying constant as the cards travel from the source to the locations of Alice and Bob. This is directly analogous to the way a local-hidden variables theory tries to explain why two experimenters always find the same spin (or opposite spin, depending on the type of particle) when they measure each member of a pair of entangled pair along the same axis. |
| May3-10, 05:00 PM | #34 |
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I think that it is simply incorrect to say that Bell was "really" responding to an actual program of Einstein's. It is more to the point to assume that Bell was, to a degree, putting words into Einstein's mouth by saying that Einstein was an advocate of a "more complete" version of QM, whereas Einstein was simply trying to prove that it is utterly fallacious to speak of QM as any kind of physical theory.
The whole idea of Einstein's advocacy of "local hidden variables," in my view, was just an attempt for certain up-and-comers to make names for themselves by way of "one upping" that most famous and venerable of all theoretical physicists. In other words, since QM is itself just a theory of the necessarily statistical nature of all possible "real world" measurements, and since Einstein upheld that a "complete" physical theory must necessarily provide a spatio-temporal representation of all aspects of the experimental scenario in question (i.e. all measuring devices and things that are to be measured), then it is senseless to say that Bell showed some kind of flaw in the reasoning of EPR. EPR, I think, was much more of a medidation on the logical foundations of any possible system of thought that can be called a "physical theory," rather than an attempt to show how an already existing theory can somehow be completed. When the EPR paper finishes... |
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