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Why no change of variable to polar coordinates inside multiloop integral ? 
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#1
Jun1210, 05:48 AM

P: 399

given a mul,tiloop integral
[tex] \int d^{4}k_{1} \int d^{4}k_{2}.................\int d^{4}k_{n}f(k_{1} , k_{2},.....,k_{n}) [/tex] which can be considered a 4n integral for integer n , my question is why can just this be evaluated by using a change of variable to 4n polar coordinates ? one we have made a change of variable and calculated the Jacobian, and integrated over ALL the angular variables we just have to make an integral [tex] \int_{0}^{\infty}drg(r)r^{4n1} [/tex] which is just easier to handle 


#2
Jun1210, 05:38 PM

Sci Advisor
P: 6,077

I don't what specific integral you have in mind, but it depends very much on the form of f as it depends on the k's. You seem to imply that it can be represented as a function g of one variable. This may be true for some particular f, but it certainly is not true in general.



#3
Jun1310, 03:43 AM

P: 399

for example
[tex] \iint dx dy \frac{x^{3}}{1+xy} [/tex] its divergent if taking the limits (0,oo) making a change of variable to polar coordinates one gets [tex] \int du \int_{0}^{\infty}dr\frac{r^{4}cos^{3}(u)}{1+(1/2)r^{2}sin(2u)} [/tex] integrating over the angular variable 'u' you have now a simple one dimensional integral 


#4
Jun1310, 04:10 PM

Sci Advisor
P: 6,077

Why no change of variable to polar coordinates inside multiloop integral ?
In general if you have an m dimensional integral and integrate over m1 dimensions, you will have a one dimensional integral. In your general case (4n) I am not sure what you mean by polar coordinates.
This question belongs in the mathematics forum. There isn't apparent connection with Beyond the Standard Model (physics). 


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