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Show that taking the coordinates of a vector WRT a basis is a linear transformation |
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| Oct10-10, 12:46 PM | #1 |
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Show that taking the coordinates of a vector WRT a basis is a linear transformation
1. The problem statement, all variables and given/known data
Suppose U is a finite dimensional vector space and A = {u1, u2, ... , un} is a basis of U. Define T : U -> R(nx1) by T(v) = [v]A. (In other words: U is an n-dimensional vector space, A is a basis for U, and T is the transformation that takes a vector in U and finds its coordinate vector with respect to the basis A.) Show that T is a linear transformation. Find kerT. 2. Relevant equations 3. The attempt at a solution If v and w are arbitrary vectors in U and a and b are scalars, we have T(av+bw) = [av+bw]A =[av1+bw1, ... , avn+bwn]A =[av1 + ... + avn]A + [bw1 + ... + bwn]A =a[v1 + ... + vn]A + b[w1 + ... + wn]A =aT(v) + bT(w) So T is a linear transformation. I just don't see if what I'm doing here is justified. Please help! Thanks. And for finding kerT, since A is a basis, it is linearly independent, so the only way to get the zero vector is to multiply everything by 0, so kerT = {0}. |
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