|Oct13-10, 03:42 AM||#1|
Water flow true a hole.
Hello every one.
This is my first post here so be gentle if i placed my topic in the wrong section.
My problem is as following.
I am trying to calculate the speed of the water wich exits true a metal plate full of cirkulare holes.
The metal plate is square and and has 14 holes each with a diameter of 14mm.
On top of the plate is a watercolum with a total hight of 50cm.
The water runs true the plate in to free air so there is no pressure working against the flow.
I want to use the calculated speed of the water to make a graph wich shows water mass on the x-axis and pressure drop on the y-axis.
I have come across following formulas:
Volume = surfuce area of holes * speed of water
press loss = zeta * (1/2)*zeta*water speed^2
I am not sure that the last calculation is correct and i have bin unable to find the zeta value in any books of mine.
im guessing its a value wich relates to the size of the hole and the dynamics of water.
I have that some of you can give me a push in the right direktion.
Sorry for spelling errors.
|Oct13-10, 03:03 PM||#2|
This is how I would do it:
In the following pictures, there are the following quantities:
p - pressure [N/m^2]
rho - density of water [kg/m^3]
v - speed of flow [m/s]
z - height of a water particle before and after the hole (the difference is approx. 0)
The weird greek letter for which I can't remember the name at the moment is a coefficient of losses for this very case ( = 1.8). I got that from my engineering handbook.
Don't forget the following:
|Oct13-10, 06:55 PM||#3|
ZalienMC: Assuming you have atmospheric pressure above the water surface in the tank, the drainage hole stream exit velocity, and the total flow rate, as a function of tank water depth, are as follows.
v = [2*g*z/(1 + ko)]^0.5 = Cd*(2*g*z)^0.5 = 2.6572*z^0.5,where v = drainage hole stream exit velocity (m/s), z = tank water depth (m), Q = total flow rate (L/s), ko = 1.778, Cd = 0.60, g = 9.8067 m/s^2, and d = drainage hole diameter = 0.014 m.
E.g., if z = 0.500 m, you have
v = 2.6572*0.500^0.5 = 1.879 m/s,
Q = 5.7265*0.500^0.5 = 4.049 L/s.
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