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Mathcad, MATLAB, Maple & Mathematica 
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#37
Oct2910, 11:44 AM

P: 3

I use mathcad and maple. i tried to learn mathamtic and matlab but i could'n
in my opinion mathcad is easier to learn from the others. 


#38
Feb2811, 09:41 PM

P: 114




#39
Mar111, 12:12 AM

P: 61

But I'm intrigued. Would it be easy to simulate, say, a number of particles bumping around in a box? 


#40
Mar111, 12:36 AM

P: 3

I say that Mathcad is easier to learn not good or bad.
I'm using Mathcad and Maple 


#41
May711, 06:01 AM

P: 10

I use matlab and there are its advantages and disadvantages:
Advantages: It lets you work in Matrices easily. It lets you do some complicated calculations quickly, without having to write a whole program or spreadsheet. Tons of addons and workbenches available to do a variety of tasks. Disadvantages: Just about everything else: horrible syntax, horrible development environment, dynamic types, not OO, a software development nightmare. It wasn't developed from a software development perspective, and it shows. Every lesson learned from the 30+ years of software development has been lost on this application, which forces users to do things that make any sensible software developer cringe 


#42
May711, 12:36 PM

P: 61




#43
Nov1113, 03:24 AM

Sci Advisor
P: 3,628

I am a bit discontent with this thread.
It would be nice for someone who knows all three programs to sum up their respective capabilities. I have worked with both Maple and Mathematica, but >5 years ago. I used to do analytic or symbolic computations and computed e.g. high order Pade approximants which required the ability to calculate with floating numbers of high precision. At least at that time, I perceived matlab as a program to do numerical, especially matrix operations, and more taylored towards engineering needs. I preferred to code matrix operations manually using lapack and the like, so I did not see a need to cope with matlab. How are the symbolic capabilities of matlab today, e.g. like finding an asymptotic expansion of the Macdonalds function with complex index? 


#44
Nov1113, 07:21 AM

PF Gold
P: 4,292




#45
Nov1213, 08:54 AM

P: 3

Hi, folks,
I'm looking to put together a toolset outside of Excel that will be used for risk analysis, forecasting, and eventually developing machinelearning algorithms for a financial services company. Excel is undeniably entrenched in ours, as in most, businesses, and that's fine. It's useful, and I think the best Microsoft product. But I'd really like to be able to work at a deeper level, both logistically and analytically, as we try to do more with our data, and as I learn how. I'm a fan of Python though still basically a neophyte. I've similarly been a fan of the Sage project (http://www.sagemath.org/) for a while and puttered around with it. I'm not sufficiently committed to nor proficient in either, nor any other particular platform that might be used for data analysis. Which is to say I'm in a position to need some more power tools and while I'm slightly predisposed to trying Python (using, perhaps, the pandas and scikitlearning libraries as well as Sage, which is developed in Python also) I'm not beholden to any particular system. I've just looked at Mathematica for the first time in a while, and considering how broad its reach is now (e.g., all of periodictable.combuilt by Wolfram Research cofounder Theodore Grayis generated with Mathematica) I'm intrigued. Matlab seems perhaps more focused on the functionality generally collected under the umbrella "data analysis". Either is, I'm sure, more than capable for beginnertointermediate sophistication. There are, of course, a variety of other options to consider as well. Buying into Matlab and Mathematica, though, is buying into some amount of proprietary technology. Conversely, starting with Python or R or other opensource tools probably means building more infrastructure by hand. Each sounds interesting, and there's some potential for overlap as they can talk to one another. But we'll be (I hope) building a department around this functionality and I'd like to start us out on solid footing. I would defer to what our tech platform uses, but we're a small business that lives on Microsoft Office, Google Apps, and a bespoke PHP application, so there's not much constraint there. Thoughts? 


#46
Nov1213, 09:12 AM

PF Gold
P: 4,292

Edit: we use maple for abstract algebra and I think it's tops for that, but their numerics aren't as well thought out as something like matlab, imo. 


#47
Nov1213, 09:15 AM

PF Gold
P: 4,292




#48
Nov1213, 12:47 PM

P: 3

Looking at Mathematica, they (predictably) also have Excelfacing functionality. However, it's an additional package costing US$249. Is Matlab's support more native? If this fits better in a separate thread, I'm happy to take that up, but I figured so many people ask about these packages (thus this sticky thread) that I'd keep it here. 


#49
Nov1213, 01:21 PM

PF Gold
P: 4,292

The functions are called xlswrite and xlsread and I'm fairly sure they're standard. Matlab also has an open file exchange where you can download free usermade packages and functions.



#50
Jul2214, 10:36 AM

P: 82

Hi friends,
First of all, sorry if my question sounds a bit elementary. I am have just started to use the 'ScientificErrorAnalysis' package in maple 17. I have some functions like: f:=Quantity(10+2*x+x^3,0.4*x) and I want to have the derivative of them. When doing diff(f, x), maple give me (D[1](`ScientificErrorAnalysis:Quantity`))(x^3+2*x+10, .4*x)*(3*x^2+2)+.4*(D[2](`ScientificErrorAnalysis:Quantity`))(x^3+2*x+10, .4*x) What does it mean by D[1] or D[2]?!!!! Is it right if I just put Quantity(2+3*x^2,0.4) instead of diff(f,x) ? Sorry, but I am always so confused with all these error functions!!! :( 


#51
Sep914, 01:52 AM

P: 2

hi
Please I need your help to plot in wolfram mathematica to plot streamline for this equation To plot streamlines, we solve the given equation for either y as a function of x and c, or x as a function of y and c. In this case, the former is easier and we have Equation for a streamline: y=(ψax3 –cx)/b A=0.5 B=2 C=1.5 Thanks 


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