Space Cannon to the Moon

midgetwars

1. The problem statement, all variables and given/known data
What are the acceleration of the cannon and the g-forces experienced if there was a guy on it...

Cannon is 215m long

Velocity is 1.66x10^4 ms^-2


2. Relevant equations
V²=u² + 2ay

3. The attempt at a solution
(1.66x10⁴)^{^2}=0 + 2xax215

a = (1.66x10⁴)[SUP]^2/2x215


Ok... So i think that's the acceleration?? I'm not sure.
I am not completely stuck on how to the g-force...

JesseC

G force is normally acceleration compared to the earths gravity we experience on the surface. So if you experience 4 G's then you're being accelerated at 4*9.81 m/s^2.

tiny-tim

hi midgetwars! welcome to pf!

(try using the X² icon just above the Reply box )

yes, that's fine

the acceleration (plus 1g) is the g-force

(yes, i know it's called a force … but it isn't! )

see http://en.wikipedia.org/wiki/G-force for some details, including …
btw, are you sure it's 215 m … that's a very long cannon!

midgetwars

So the a is

so i got 26 1302.3256 ms^0-2...

That means the g-forces are around 26 000 gs??? That's seems to be a lot don't you think?? Also wikipedia says the acceleration isn't that high, but doesn't offer a solution


a = (1.06x10⁴)² / 2x215

tiny-tim

how did you get that?

EDIT: oh you've just changed it

midgetwars

So is that right?

tiny-tim

a = (1.66x10⁴)²/2x215 is right

midgetwars

so the G forces would be + 1...?

tiny-tim

+ g, yes