
#1
Nov610, 03:13 PM

P: 12

we know that [tex]\int_{yz}^{y+z}D(y,z,w)\frac{w^{2m+1}}{2^m\Gamma(m+1)}dw=1
[/tex] how can we calculate the integral [tex]\int_{yz}^{y+z}(1+2^kw)^aD(y,z,w)\frac{w^{2m+1}}{2^m\Gamma(m+1)}dw[/tex] 



#2
Nov610, 08:00 PM

P: 83

just a shot in the dark, but maybe integration by parts. if you can somehow make the first part of that integral disappear, you can finish it off.




#3
Nov1510, 06:05 AM

P: 24

integration by parts would be a method to use but the problem would be integrating the (1+2^kw)^a part but if you choose u(x) and v(x) appropriately you will solve the problem since you already know that the first integral with the same limits does equal 1.



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