| Thread Closed |
integration by parts |
Share Thread |
| Aug29-04, 02:06 AM | #1 |
|
|
integration by parts
hi, i would like help on a problem i am currently stuck on.
[tex]\int(e^x)/(1+e^(2x))dx[/tex] <-- it's suppose to be [tex]\int[/tex] (e^x)/(1+e^(2x))dx using integration by parts, here's what i done: u=e^x du=e^x dv=(1+e^(2x)) v = (need to use anti-differentiation, which i dont remeber....) can i use integration by parts with this? this is cal 2. |
| Aug29-04, 05:26 AM | #2 |
|
|
|
| Aug29-04, 07:26 AM | #3 |
|
Recognitions:
|
Erm, by-parts doesn't seem to make sense because actually:
[tex]u = e^x[/tex] [tex]dv = \frac{1}{1 + e^{2x}}[/tex] To me, it just looks like it is going to get nastier and nastier. I would suggest using the substitution [itex]t = e^x[/itex] because [itex]dt = e^xdx[/itex] and if you look at the integral like this it becomes quite simple: [tex]\int \frac{e^x dx}{1 + \left( e^x \right)^2} [/tex] |
| Aug30-04, 02:43 PM | #4 |
|
Recognitions:
|
integration by partsI would not try an integration by parts. I would simply do a simple substitution u= e^x. Then you have the integral of du/(1+u^2) which is a basic one. Pat |
| Thread Closed |
Similar Threads for: integration by parts
|
||||
| Thread | Forum | Replies | ||
| Integration problems. (Integration by parts) | Calculus & Beyond Homework | 5 | ||
| integration by parts | Calculus & Beyond Homework | 1 | ||
| integration by parts | Calculus | 6 | ||
| Integration by Parts | Calculus & Beyond Homework | 1 | ||
| Using Integration by Parts | Calculus & Beyond Homework | 5 | ||