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Planet X and a Satellite

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thelightsare
#1
Dec31-10, 10:33 PM
P: 9
1. The problem statement, all variables and given/known data

Planet X has a mass of 6.42x10^20 kg and a radius of 2400km. A satellite with a mass of 1500kg is in orbit around Planet X at an altitude of 300km.
a) what is the Force of Gravity?
b) What is the acceleration of the satellite while in orbit?
c) Find the speed of the satellite in orbit.
d) Find the period of the satellite.


2. Relevant equations

F = GMm/r^2, maybe f=ma , a = v^2/r?, T= 2 pi r/v

3. The attempt at a solution

a)
F=GMm/r^2
F=6.67e-11*6.42e23*2000/(3400+300)^2
F[tex]\approx[/tex]6.26e9 N ?

b) very unsure but can you use
f=ma
6.26e9 N=2000a
and solve for a or is tht wrong? I was also maybe thingking of using

c) v = ?
could you use a = v^2/r
a(take answer from b) = v^2/(3400+300) and solve for v
or is this the wrong equation or wrong values?

d)T= 2 pi r/v
T = 2 pi (3400+300)/v(answer from c) ???

Thanks!
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ehild
#2
Jan1-11, 12:02 AM
HW Helper
Thanks
P: 10,381
Your method is correct, but the numbers you plugged in for the masses and radius of the planet do not much with the data given.

ehild
thelightsare
#3
Jan1-11, 12:18 AM
P: 9
Quote Quote by ehild View Post
Your method is correct, but the numbers you plugged in for the masses and radius of the planet do not much with the data given.

ehild
I always have a problem telling which data to use. Any hints or suggestions?

gneill
#4
Jan1-11, 12:35 AM
Mentor
P: 11,621
Planet X and a Satellite

Quote Quote by thelightsare View Post
I always have a problem telling which data to use. Any hints or suggestions?
Seriously? How about reading the question carefully, using the data that's provided, and checking your figures?

There is no magic formula to help with that!
thelightsare
#5
Jan1-11, 12:59 AM
P: 9
Quote Quote by gneill View Post
Seriously? How about reading the question carefully, using the data that's provided, and checking your figures?

There is no magic formula to help with that!
I just really have trouble deciding which mass to use and wether "r" would mean to use the dist. between objects or the radius. I really really really want to understand and would love any help! Also, how do u check ur answers? It seems like valuable information to know.
ehild
#6
Jan1-11, 01:07 AM
HW Helper
Thanks
P: 10,381
Read the text of the problem and compare with the data you used when calculating the force: the mass of the planet is 6.42x10^20 kg. It is M. You substituted 6.42x10^23 kg for M. The mass of the satellite is 1500 kg. You substituted 2000 kg for m. The radius of the planet is 2400 m. You plug in 3400 m.


ehild
thelightsare
#7
Jan2-11, 11:42 AM
P: 9
Quote Quote by ehild View Post
Read the text of the problem and compare with the data you used when calculating the force: the mass of the planet is 6.42x10^20 kg. It is M. You substituted 6.42x10^23 kg for M. The mass of the satellite is 1500 kg. You substituted 2000 kg for m. The radius of the planet is 2400 m. You plug in 3400 m.


ehild
Oh! THank you so much!
thelightsare
#8
Jan2-11, 12:03 PM
P: 9
One quick last question. For a = v^2/r and T= 2 pi r/v would r =2400+300 or just 2400?
ehild
#9
Jan2-11, 12:20 PM
HW Helper
Thanks
P: 10,381
r=2700 km

ehild
thelightsare
#10
Jan2-11, 12:26 PM
P: 9
Quote Quote by ehild View Post
r=2700 km

ehild
Great! Thanks so much


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