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Modifying iteration of DO-loop dynamically

by chaim
Tags: do-loop, iteration, modify
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chaim
#1
Jan23-11, 12:53 AM
P: 5
I would like to change the start integer for a DO-loop each time the DO runs as a result of the calculations of the previous iteration. For example the first time the DO runs it should start at 1, the second time at 33, the third time at 60. The numerical value for the end of the loop stays the same. I have tried to change the iterator dynamically as can be seen in the code below, but the g77 gives an error.

ACS = 1
NUME = 0
DO 12, AC = ACS,NH

IF (VI(AC) .NE. 100.0) THEN
VF(AC) = VI(AC)
GOTO 12

ELSEIF (VI(AC) .EQ. 100.0) THEN
DO 80,AB = AC,AC+24
IF (VI(AB) .EQ. 100) NUME = NUME + 1
IF (VI(AB) .NE. 100) GOTO 81

80 CONTINUE
81 IF ((VI(AC-1)- VI(AC+NUME)) .GT. 0.0) THEN
DO 77, VAL = AC,AC+NUME+1
VF(VAL)=VI(AC)-((VI(AC-1)-VI(AC+NUME))/(NUME+1))

77 CONTINUE

ELSEIF ((VI(AC-1)- VI(AC+NUME)) .LT. 0.0) THEN
NUM = 0
DO 99, VAL = AC,AC+NUME-1
NUM = NUM + 1
VF(VAL)=VF(AC+NUM-2)+((VI(AC+NUME)-VI(AC-1))/(NUME+1))
AC = VAL -1 <=== compiler error
99 CONTINUE

How can I modify AC without getting a compiler error or is an alernative logic necessary??
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Antiphon
#2
Jan23-11, 01:02 AM
P: 1,781
You cannot do it with a do loop. You must construct one out of goto and if statements. You are then free to modify the dummy variable any way you like.
jtbell
#3
Jan23-11, 07:27 AM
Mentor
jtbell's Avatar
P: 11,781
Or use a DO WHILE loop. The following two loops are equivalent:

      do 99 k = start, stop
          print *, k
99    continue
      k = start
      do 99 while (k .le. stop)
          print *, k
          k = k + 1
99    continue
except that with the DO WHILE loop you can modify the loop index variable inside the loop (in fact, that's what this example does!) whereas with the regular DO loop you can't.


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