inflection point of non continuous or non differentiable functionby player1_1_1 Tags: continuous, differentiable, function, inflection, point 

#1
Feb1111, 04:29 AM

P: 118

1. The problem statement, all variables and given/known data
three functions: [tex]y=\begin{cases}\arctan \frac{1}{x}\ x\neq0\\ 0\ x=0\end{cases}[/tex] [tex]y=\frac{1}{x}, y=x^21[/tex] and what about inflection point? 3. The attempt at a solution first function is concave on left of 0, convex on right, so from definition it should be inflection point, but its not continuous in this point, a function need to be continuous in this place or not? in 2, [tex]x=0[/tex] should be inflection point, but its not in the domain, so is there inflection point? in 3, function is continuous in [tex]x=1[/tex] but not differentiable, is there inflection point or not? 



#2
Feb1111, 02:29 PM

P: 118

up,.




#3
Feb1111, 02:42 PM

HW Helper
Thanks
PF Gold
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#4
Feb1211, 02:14 AM

P: 118

inflection point of non continuous or non differentiable function
thx!



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