# inflection point of non continuous or non differentiable function

by player1_1_1
Tags: continuous, differentiable, function, inflection, point
 P: 118 1. The problem statement, all variables and given/known data three functions: $$y=\begin{cases}\arctan \frac{1}{x}\ x\neq0\\ 0\ x=0\end{cases}$$ $$y=\frac{1}{x}, y=|x^2-1|$$ and what about inflection point? 3. The attempt at a solution first function is concave on left of 0, convex on right, so from definition it should be inflection point, but its not continuous in this point, a function need to be continuous in this place or not? in 2, $$x=0$$ should be inflection point, but its not in the domain, so is there inflection point? in 3, function is continuous in $$x=1$$ but not differentiable, is there inflection point or not?
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 Quote by player1_1_1 1. The problem statement, all variables and given/known data three functions: $$y=\begin{cases}\arctan \frac{1}{x}\ x\neq0\\ 0\ x=0\end{cases}$$ $$y=\frac{1}{x}, y=|x^2-1|$$ and what about inflection point? 3. The attempt at a solution first function is concave on left of 0, convex on right, so from definition it should be inflection point, but its not continuous in this point, a function need to be continuous in this place or not? in 2, $$x=0$$ should be inflection point, but its not in the domain, so is there inflection point? in 3, function is continuous in $$x=1$$ but not differentiable, is there inflection point or not?
It probably depends on the definition your text gives. Most say it must be a point on the graph where the concavity changes. That would rule out the first two. I would say the third qualifies because of the change in concavity at the point. But your mileage may vary.

P: 118

## inflection point of non continuous or non differentiable function

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