EM Differential Form version of Lagragian


by haloempty
Tags: action, differential form, maxwell's equations, variational method
haloempty
haloempty is offline
#1
Feb27-11, 11:48 PM
P: 2
Given that we have the one form A we can get the F=dA, and I see how dF=0 and d*F=J, give maxwell's equations. But if we write the Action as [tex]\int[/tex]1/2dA[tex]\wedge[/tex]*dA+A[tex]\wedge[/tex]J how do we go about doing a variational procedure to get d*dA=J? I tried taking d(Lagrangian)=0 but that seemed to be off by a factor of 2. I guess I'm not sure how you vary an action when your lagrangian is composed of forms. Any ideas?
Phys.Org News Partner Science news on Phys.org
Scientists pinpoint when harmless bacteria became flesh-eating monsters
Asian air pollution affect Pacific Ocean storms
Rocket leak delays space station delivery launch (Update)

Register to reply

Related Discussions
Differential form Calculus & Beyond Homework 2
L2 Lagragian point? Classical Physics 8
differential form Differential Geometry 3
differential form Differential Geometry 0