New Reply

Eigenvalues of Laplacian with Boundary Condition

 
Share Thread
Mar31-11, 08:28 PM   #1
 

Eigenvalues of Laplacian with Boundary Condition


Given a bounded domain with the homogeneous Neumann boundary condition, show that the Laplacian has an eigenvalue equal to zero (show that there is a nonzero function u such that ∆u = 0, with the homogeneous Neumann B.C.).

I said: ∇•(u∇u)=u∆u+∇u2, since ∆u = 0, we have ∇•(u∇u)=∇u2

∫ ∇•(u∇u) dV = ∫ ∇u2 dV, and by divergence theorem on the left hand side, we get ∫ (u∇u)•dS=∫ ∇u2 dV, but since ∇u is zero on the boundary, we have

∫ ∇u2 dV=0. Since the integrand is non-negative, ∇u=0, which means u is constant.

This can't be the right answer, could it?! It seems way to trivial, I could have just said if u is constant, then it satisfies the question trivially...Did I do something wrong? am I misunderstanding the question?
PhysOrg.com science news on PhysOrg.com

>> City-life changes blackbird personalities, study shows
>> Origins of 'The Hoff' crab revealed (w/ Video)
>> Older males make better fathers: Mature male beetles work harder, care less about female infidelity
Apr1-11, 05:52 PM   #2
 
bump
New Reply

Tags
eigenvalue, laplacian, neumann

Similar discussions for: Eigenvalues of Laplacian with Boundary Condition
Thread Forum Replies
Eigenvalues of Laplacian on parametric surface Differential Equations 0
Electrostatics - Where does this boundary condition come from? Advanced Physics Homework 0
Types of boundary condition Differential Equations 0
NEED HELP! Boundary Condition Problem Engineering, Comp Sci, & Technology Homework 0
Boundary Condition Calculus & Beyond Homework 7