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Trying to understand weather balloons better (ideal gas law) 
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#1
May2311, 11:30 PM

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Here's my understanding....
(P1V1)/T1 = (P2V2)/T2 P1 = starting pressure, typically sea level pressure which is 1atm. V1 = Starting volume of the gas inside your balloon. T1 = starting temperature, temperature at ground level. P2 = final pressure, this should be the pressure at your flight altitude. V2 = final volume, should be 100% of balloon capacity. T2 = final temperature, temp at flight altitude. Now i'm trying to understand this from a lighter than air gas standpoint, so... Do i assume that: P1, T1 are what i stated above, and do i assume that P2, T2 are proportional, if the gas isn't heated by a secondary source such as a hot air balloon? Thanks in advance, will post further questions once these are validated or corrected! 


#2
May2311, 11:54 PM

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#3
May2411, 12:31 AM

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The weight of the gas?



#4
May2411, 12:40 AM

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Trying to understand weather balloons better (ideal gas law)



#5
May2411, 01:13 AM

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If there wasn't a limit on how much the balloon could expand (about 100 to 1 volume wise), a hydrogen filled weather balloon could reach the outer layer of atmosphere, above low orbiting objects. 


#6
May2411, 02:01 AM

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So basicly a balloon is limited by: V1 amount of gas needed to take off then V2 gas volume is maxed out at whatever altitude. 


#7
May2411, 02:13 AM

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So if i had V1 = 1m^3 of hydrogen weight of 0.0899kg/m^3
how do i determine what its V2 would be at different heights? 


#8
May2411, 02:59 AM

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#9
May2411, 11:43 PM

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#10
May2511, 10:43 AM

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