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Trigometric Proof |
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| Jun12-11, 09:52 AM | #1 |
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Trigometric Proof
I am having trouble proving the following trigonometric equation:
cosx + cos3x +cos5x = sin6x/2sinx Any help would be appreciated |
| Jun12-11, 10:15 AM | #2 |
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Recognitions:
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You'll need to show us your attempt before we can help you. I assume that you are familiar with the trigonometric identities (particularly, the sum/difference & multiple-angle identities).
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| Jun12-11, 02:40 PM | #3 |
Recognitions:
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Are you familiar with complex numbers and Euler's formula?
ehild |
| Jun12-11, 03:45 PM | #4 |
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Trigometric ProofSince this is in terms of x, I would try to use the identity (sin(x+x))= ... to get the whole thing in terms of single variables. For example sin(5x) is really sin(4x+x) which can expand, and then sin(3x+1) expands out and so on. Then it should be easy to simplify. |
| Jun17-11, 01:26 PM | #5 |
Recognitions:
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Try to write both sides in terms of cos(3x) and cos(x), using the addition rules. (x=3x-2x, 5x=3x+2x, 6x=2*(3x) ).
ehild |
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| algebra, proof, trigonometry |
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