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Calculus of Variations |
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| Jul31-11, 11:01 AM | #1 |
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Calculus of Variations
Hi, why is it true that for [tex]\vec{x^\varepsilon}=\frac{\vec{x(t)}-\varepsilon \vec{y(t)}}{|\vec{x(t)}-\varepsilon \vec{y(t)}|}[/tex],
[tex]\frac{\partial}{\partial x} |\vec{\dot{x}}|^2=-2 |\vec{\dot{x}}|^2 \vec{x}[/tex] at [tex]\varepsilon[/tex]=0? Thanks. |
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