Does Time Move Differently on the Space Shuttle?

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Discussion Overview

The discussion centers around the effects of time dilation experienced by clocks on the space shuttle compared to those on Earth. Participants explore the implications of speed and gravitational effects on time measurement, raising questions about the nature of time in different frames of reference.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants suggest that clocks on the space shuttle run more slowly than those on Earth due to the shuttle's speed, while others argue that the altitude reduces gravitational effects, potentially causing clocks to run faster.
  • A participant proposes that the net effect results in clocks on the shuttle running faster than those on Earth, though this is contested.
  • One participant emphasizes that the mechanics of atomic clocks differ from traditional clocks, suggesting that gravity does not affect them in the same way.
  • Another participant provides a mathematical framework to describe the rate of time flow for objects in Earth's gravitational field, indicating that the velocity effect may outweigh the altitude effect for the shuttle.
  • There is a discussion about the differences in time dilation effects between the space shuttle and GPS satellites, with one participant asserting that the effects are not the same due to their respective orbits.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the effects of time dilation for the space shuttle. Multiple competing views remain regarding whether the clocks on the shuttle run faster or slower compared to those on Earth, and the discussion reflects ongoing uncertainty and debate.

Contextual Notes

Some claims rely on specific assumptions about the nature of time and the mechanics of different types of clocks. The discussion includes unresolved mathematical steps and varying interpretations of the effects of speed and altitude on time measurement.

sam1967
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I just read that the clocks on board the space shuttle go more slowly than the clocks on earth.
does that mean time has speeded up for those on the shutte or slowed down ?
i reckon it means time has slowed down. if they stayed up for a year by their clocks then by our clocks more than a year will have passed.
 
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Is this a question, or statement?
 
it was a question as I am really not sure.
 
Originally posted by sam1967
it was a question as I am really not sure.
So maybe you would want to type in the words "time dilation" into the search feature, (in these forums) look in titles, or threads, and you will find some 'stuff' to help you start building knowledge towards understanding the how and why of that...stuff... O.K.?
 
The speed of the space shuttle causes the clocks to slow down relative to a clock on earh. The altitude (reduced gravitational force) causes the clocks to speed up. The net effec is that the clocks (time) go faster in space than on earth.
 
Originally posted by russ_watters
The speed of the space shuttle causes the clocks to slow down relative to a clock on earh. The altitude (reduced gravitational force) causes the clocks to speed up. The net effec is that the clocks (time) go faster in space than on earth.
And hence the relativisation of light's speed(?)
 
Mr. Robin Parsons - Your second post was uncalled for. There was nothing wrong with the question. Yes, sam1967 could have used the search feature to find some similar topic...but give a new member a break. I'd rather see repeated discussions than rude responses.
 
Originally posted by Mr. Robin Parsons
And hence the relativisation of light's speed(?)

no, the relativisation of time
 
Originally posted by Phobos
Mr. Robin Parsons - Your second post was uncalled for. There was nothing wrong with the question. Yes, sam1967 could have used the search feature to find some similar topic...but give a new member a break. I'd rather see repeated discussions than rude responses.
O.K. but I was trying something trying to see if I could help, the rude part, is, perhaps, not as much there, as you might think...But I would apologise to sam1967 if they were, what? "off-ended" by my, well, thought...Sorry sam1967, didn't intend, or mean to be 'rude' just wondered if newbies even looked in the search features, they are rich... My Opinion...
 
  • #10
thanks
 
  • #11
No Problemo
 
  • #12
You might be incorrect, the clocks on the shuttle are not your wind up clocks next to your bed.
They are digital and atomically. gravity does not effect the mechanics of the clock because there are no gears, weights,springs in it.
 
  • #13
You noticed, didn't you, that this thread was 7 years old?
 
  • #14
Lol. Space time even exists in forums.
 
  • #15
just board said:
You might be incorrect, the clocks on the shuttle are not your wind up clocks next to your bed.
They are digital and atomically. gravity does not effect the mechanics of the clock because there are no gears, weights,springs in it.

To observers on the shuttle, the clocks are running at their usual rate, irrespective of whether they are mechanical or digital. However, according to russ waters, to observers on the Earth's surface, the clocks on the shuttle are running faster than their own, and it is Earth surface clocks that are running at the usual rate.
 
  • #16
Chestermiller said:
However, according to russ waters, to observers on the Earth's surface, the clocks on the shuttle are running faster than their own, and it is Earth surface clocks that are running at the usual rate.

I don't think russ's statement was correct for the Space Shuttle. It is correct for satellites in high orbits, such as the GPS satellites, where the effect of altitude (speeding up clocks relative to those on the Earth's surface) outweighs the effect of orbital velocity (slowing down clocks relative to those on the Earth's surface). For satellites in low Earth orbit, such as the Shuttle, the velocity effect outweighs the altitude effect.

An approximate equation for the rate of time flow for an object in Earth's gravity field is

[tex]\frac{d\tau}{dt} = \sqrt{1 - \frac{2 G M}{c^{2} r} - \frac{v^{2}}{c^{2}}}[/tex]

For an object on Earth's surface, we can eliminate the v^2 term by using the poles as a reference; since the Earth's surface is (approximately) an equipotential surface, clocks on the surface all go at the same rate, and the rate at the poles is the easiest to calculate. The polar radius of the Earth is 6.36 x 10^6 meters according to Wikipedia. G is 6.67 x 10^-11, and M for the Earth is 5.97 x 10^24 kg. This gives a result of [itex]d\tau / dt = 1 - 6.97 * 10^{-10}[/itex].

For objects in orbit, since v^2 = GM/r for an object in a free-fall circular orbit (which we'll assume is a good enough approximation for this problem), we can rewrite the above more simply as

[tex]\frac{d\tau}{dt} = \sqrt{1 - \frac{3G M}{c^{2} r}}[/tex]

For the Space Shuttle, r is about 200 miles, or 3.2 x 10^5 m, above the Earth's surface. For the GPS satellites, r is about 4.2 Earth radii. The corresponding numbers are:

Shuttle: [itex]d\tau / dt = 1 - 9.95* 10^{-10}[/itex], which is slower than ground clocks by about 3 parts in 10^-10.

GPS satellite: [itex]d\tau / dt = 1 - 2.49 * 10^{-10}[/itex], which is faster than ground clocks by about 4.5 parts in 10^-10.
 
  • #17
HallsofIvy said:
You noticed, didn't you, that this thread was 7 years old?
And now it is over 8 years old.

Thread locked.
 

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