What is the value of Mu needed for orbit calculations in the Earth-moon system?

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SUMMARY

The value of Mu (GM) for orbit calculations in the Earth-moon system is determined by using the gravitational constant (G) multiplied by the mass of the Earth. For planetary calculations, Mu is calculated using the formula Mu = GaussK * GaussK * (1 + mass), where GaussK is the Gaussian constant (0.01720209895) and mass is the planet's mass relative to the sun. For the moon's orbit, it is essential to maintain the same routine, but the new Mu must reflect the Earth's gravitational influence. Additionally, the Gaussian constant for sun-relative orbits is 2 pi / 365.256898326.

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  • Basic principles of MKS units and their application in orbital simulations
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kepler
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Hi again,

I was able to solve the previous problems I had, with some study over the net and some books.
Now I have a different problem: I have a routine that uses Mu (GM) for calculations; for the planets, Mu = GaussK * GaussK * ( 1 + mass ), where GaussK is the Gaussian constant (0.01720209895) and mass is the mass of the planet divided by the mass of the sun ( for earth, mass = 1/328900.56, for example ).
Now, I want to use the same routine, but for the orbit of the moon around the earth. which value of Mu must I use to maintain the proportion and the functionality of the routine?

Please someone answer as soon as possible.

Kepler
 
Last edited:
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kepler said:
Hi again,

I was able to solve the previous problems I had, with some study over the net and some books.
Now I have a different problem: I have a routine that uses Mu (GM) for calculations; for the planets, Mu = GaussK * GaussK * ( 1 + mass ), where GaussK is the Gaussian constant (0.01720209895) and mass is the mass of the planet divided by the mass of the sun ( for earth, mass = 1/328900.56, for example ).
Now, I want to use the same routine, but for the orbit of the moon around the earth. which value of Mu must I use to maintain the proportion and the functionality of the routine?

Please someone answer as soon as possible.

Kepler
I don't do canonical units for anything except sun-relative orbits. For orbit simulations and transfer calculations in the Earth-moon system, I'd stay with MKS units. In fact, there's so much perturbing going on throughout most of this volume that I'd probably use rotating coordinates and include the centrifugal, coriolis and torquey force terms, as well as a time-dependent force vector for the solar perturbation. The rotating system would have a varying angular speed, in order to keep the Earth and moon on the X axis, hence the need for the torquey force term.

But if you confine yourself to low Earth orbits, your new Mu would be the gravitational constant (G) multiplied by the mass of Earth. As for your new GaussK, remember that the Gaussian constant for sun-relative orbits is equal to 2 pi / 365.256898326. It's a handy number for getting other planets' orbits scaled in comparison to Earth's orbit.

Jerry Abbott
 
Last edited:

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