
#1
Oct2804, 11:47 PM

P: 8

I don't know how to calculate the following rigid bodies with different geometries, can anybody help me?
Thin spherical shell: I=(2/3)MR^2 Solid sphere: I=(2/5)MR^2 Thanks in advance. 



#2
Oct2904, 01:03 AM

Sci Advisor
HW Helper
P: 3,149

Use the definition of moment of inertia:
[tex]I = \int r^2 dm[/tex] In the case of the shell the element of mass is [itex]dm = M {dA} /{4 \pi R^2}[/itex] where [itex]dA = R^2 \sin \theta d\theta d\phi[/tex]. The distance to a point on the shell from the zaxis is [itex]R^2 \sin^2 \theta[/itex] so [tex]I = \frac {M}{4 \pi R^2} \int_{0}^{2 \pi} d\phi \int_{\pi /2}^{\pi /2}R^4 \sin^3 \theta d\theta[/tex] from which the desired result follows. In the case of the solid sphere you will work with a volume integral. 



#3
Oct3004, 09:08 AM

P: 8

Could you please explaim why [itex]dA = R^2 \sin \theta d\theta d\phi[/tex] in detail?




#4
Oct3004, 01:04 PM

Sci Advisor
HW Helper
PF Gold
P: 12,016

How to calculate the moment of inertia of the rigid body?We approximate this with a rectangle: a)Two of the sides are arclengths along great circles; the length of each of these is [tex]Rd\theta[/tex] b) The other two are arclengths in THE HORIZONTAL PLANE; the local radius there is [tex]R\sin\theta[/tex] Hence, the arclenth is [tex]R\sin\theta{d\phi}[/tex] c) Multiplying together, we get: [tex]dA=R^{2}\sin\theta{d\theta}d\phi[/tex] 



#5
Oct3004, 01:06 PM

Sci Advisor
HW Helper
P: 3,149




#6
Nov204, 03:26 AM

P: n/a

This is the first time i'm involved in physics studies.I'm having a lots of problems using these formulas and the text book i'm using does not make it easy. one from "James S. Walker"
Can someone please explain how and when to use these formulas. Thank You. 



#7
Nov204, 04:15 AM

HW Helper
PF Gold
P: 1,198

This is one way to look at it
You must be familiar with the equation F=ma. We use the Moment of Inertia to find the Torque. Like how the force is directly propotional to acceleration, Torque is directly propotional to angular acceleration, the propotionality constant being the moment of inertia. Also remember about what axis you are taking the moment of Inertia while solving problems. In most problems i have encounterd which ask you to find the angular acceleration, first find the torqure taking the vector product R X F. Next find the moment of inertia of the object about the required axis. Then the acceleration can be found Also, for a solid sphere, perphaps deriving the moment of inertia by intergrating thin rings would be easier than a volume intergral? 


Register to reply 
Related Discussions  
Moment of Inertia Tensor for a Flat Rigid Body  Advanced Physics Homework  0  
Rigid body moment of inertia  Introductory Physics Homework  4  
Newtonian mechanics  extended rigid body's rotation, moment of inertia  Introductory Physics Homework  1  
Moment of Inertia of Human body  Advanced Physics Homework  4 