|Nov24-11, 10:10 PM||#1|
Leyden jar resulting amperage
I need to figure out how to correctly calculate the Current being created from a leyden jar I have. I am attaching a print screen of a matchcad calculation that shows what I have done. However, I am calculating extremely high amperage. I believe my calculation is correct down to my charge, but I do not know how to correctly relate my charge to the resulting amperage. Have a look!! any suggestions please!!
|Nov25-11, 01:10 AM||#2|
If you discharge a near-ideal capacitor with an almost perfect conductor, there will be a momentary pulse of current approaching infinite amperes. Non-ideal components reduce the amplitude, and extend the duration.
|amperage, charge, current, leyden jar|
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