| New Reply |
a set A of n elements has n(n-1)/2 subsets of 2 elements |
Share Thread |
| Dec11-11, 12:59 PM | #1 |
|
|
a set A of n elements has n(n-1)/2 subsets of 2 elements
I would very much like some help to the following problem.
1. The problem statement, all variables and given/known data Using mathematical induction, prove that a finite set A of n elements has n(n-1)/2 subsets of two elements. 3. The attempt at a solution * Base step n=2: 2(2-1)/2= 1 subset of two elements. * Inductive step: assuming the statement holds for n=k, that is a set A of k elements has k(k-1)/2 (hypothesis) We want to show that it also holds for n=k+1, that is a set A of k+1 has (k+1)(k+1-1)/2 elements. How can we infer from the hypothesis ??? I have no idea ... I have an engineering background so be as descriptive as you can. Thank you in advance. |
| Dec11-11, 01:26 PM | #2 |
|
Recognitions:
|
Suppose you add a new element to set A. How many new subsets can be created where one of the elements of these subsets is the new element? |
| Dec11-11, 01:46 PM | #3 |
|
|
if we add an element to the set which previously had k elements (that is now has k+1 elements) the new subsets that include the new element will be :
(k+1)k/2 - k(k-1)/2 = k So, how can we argue that this will solve the problem ? |
| New Reply |
Similar discussions for: a set A of n elements has n(n-1)/2 subsets of 2 elements
|
||||
| Thread | Forum | Replies | ||
| subsets of a set such that no two have two equal elements | Calculus & Beyond Homework | 0 | ||
| Prove the intersection of nested subsets containing infinite elements is infinite | Calculus & Beyond Homework | 7 | ||
| Question: Can elements above iron actually be clusters of smaller elements? | Atomic, Solid State, Comp. Physics | 3 | ||
| Kronecker product on only a few elements in a matrix: How to align resulting elements | Linear & Abstract Algebra | 0 | ||
| Confused on directions, List the elements in the subsets? | Calculus & Beyond Homework | 2 | ||