# Black Hole Temperature

by sabanation12
Tags: black, hole, temperature
 P: 21 Ok so first I know that this equation was presented by Stephen Hawking to describe to Temperature of a black hole: T = hc2 / 16∏2GMk so I did the calculations and got that the temperature of a black hole with the mass of our sun would be ≈ .57° Is this right? Is this the right equation? Here is what I used for the variables can you guys check if these are correct?: g = 6.67*10^-11 h = 62606956*10^-34 k = 1.3806583*10^-23 and then just the mass of our sun and the speed of light Thanks
 PF Gold P: 184 I'm getting closer to 10-16 °K, so a Black Hole Sun would evaporate very slowly, unlike the Soundgarden video.
 Sci Advisor P: 4,721 Looks like you missed a factor of the speed of light in your equation. Should be: $$T = {h c^3 \over 16\pi^2 GMk}$$ Anyway, the easiest way to calculate these things is to just plug them into Google. The Google calculator knows about units, fundamental constants, and a lot of common values, so you can simply type in: h*c^3/(16*pi^2*G*(mass of sun)*k) ...to Google, and it will give you the right result (about 10^-8 K). Oh, and there's also a nifty calculator for all of the values related to a black hole: http://xaonon.dyndns.org/hawking/
PF Gold
P: 9,182

## Black Hole Temperature

Shouldn't that be $$\hbar c^3 / 8 \pi GMk$$ or did I miss something?
 Quote by Chronos Shouldn't that be $$\hbar c^3 / 8 \pi GMk$$ or did I miss something?
It's just a difference of whether to use $h$ or $\hbar$ :)