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Antisymmetric connection (Torsion Tensor) |
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| Feb5-12, 05:28 AM | #1 |
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Antisymmetric connection (Torsion Tensor)
How to show:
Tabc = [itex]\Gamma[/itex]abc - [itex]\Gamma[/itex]acb is a Tensor of rank (1,2) Attempted solution: 1. Using definition of Covariant Derivative: DbTa= ∂aTa+[itex]\Gamma[/itex]abcTc (1) DcTa= ∂cTa+[itex]\Gamma[/itex]acbTb (2) I subtracted (2) from (1) but I couldn't really get a Tensor out of it. I just got lost in the mess. Is this is the right way to start it? |
| Feb6-12, 10:57 AM | #2 |
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Do you have to use covariant derivatives in your problem? Is it a hint in your problem? There are several ways to show your property.
And why do you say "antisymmetric connection?" |
| Feb6-12, 11:08 AM | #3 |
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I am also in the process of learning tensor calculus, so I may not be right, but wouldn't it work if you raised the indices and made every tensor ab-contravariant?
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| Feb6-12, 11:13 AM | #4 |
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Antisymmetric connection (Torsion Tensor)
Which text are you using? There are different ways of showing your property, but the method should be adapted to what you already know.
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| Feb6-12, 11:40 AM | #5 |
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@arkajad: Covariant derivative is not a hint in the problem. I am just trying to solve that way. I am following various kind of textbooks. So, any way would work for me.
@meldraft: I am sure if that will work. Since the purpose of this exercise is to show how the difference between two Christoffel symbols that are asymmetric gives rise to torsion tensor. |
| Feb6-12, 11:50 AM | #6 |
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Check Eq. (3.6) in http://preposterousuniverse.com/grno...otes-three.pdf But do not read further than that!!!! |
| Feb7-12, 05:24 PM | #7 |
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Solved.
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| general relativity, tensor calculus |
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