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Rate Laws - Pseudo-Order

by ThirdEyeBlind
Tags: laws, pseudoorder, rate
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ThirdEyeBlind
#1
Feb12-12, 03:53 PM
P: 11
1. The problem statement, all variables and given/known data
2A + 2B -> C +D
where rate = k [A] [B]^2
[A]_0 = .000443 M
[B]_0 = 1.69 M
A plot of ln [A] vs time has a slope of -9.87. What will the rate of this reaction be when [A]=[B]=1.412 M?


2. Relevant equations



3. The attempt at a solution
From given information, this is pseudo-first order. So slope=-k so k = 9.87 but this is pseudo-order so k'= 9.87

rate= k' [A]
k' = k [B]^2 --> k = k' / [B]^2 and I plug in the values for k' and [B] = 1.412 and I get the wrong answer. The answer should be 9.73 M/s
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