## Deriving the Gaussian density probability equation

Hey ^^, new here but I already have a question haha

Does anyone here know how the coefficient (x-μ)^2 was derived in the following equation:

σ^3=(1/√2∏)∫(1/σ)*(x-μ)^2*exp((x-μ)^2)/(2σ^2))

I know the general equation for density probability is (1/σ)*exp((x-μ)^2)/(2σ^2))
but in this case I can't quite see how the coefficient came about... any help?

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 Your expression looks wrong to me. Could you check it for accuracy?
 Recognitions: Science Advisor It looks like it should be σ2. The expression is essentially the definition of the variance, the second moment of the distribution centered at the mean.

## Deriving the Gaussian density probability equation

Oh I'm sorry that was an error on my part, it is indeed σ^2

σ^2=(1/√2∏)∫(1/σ)*(x-μ)^2*exp((x-μ)^2)/(2σ^2))

Ah thank you so much mathman ^^, that's what I was looking for! I'm studying engineering so sometimes they just throw mathematical equations at us with no explanation ¬_¬.

 Tags density function, gaussian