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Why does resonance greatly increase the likelihood of the triple alpha process?

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cragwolf
#1
Mar5-12, 04:31 PM
P: 210
Why does the fact that the combined energy of 8Be and 4He is (almost) the same as the energy of an excited state of 12C greatly increase the probability of that reaction (i.e. 8Be + 4He → 12C + stuff) occurring? Apparently it doesn't have to be exactly the same, but does it make any difference if it's slightly less vs slightly more?
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QuantumPion
#2
Mar6-12, 04:32 PM
P: 778
All atoms have lower mass than the sum of their parts. This difference is called binding energy, and is the reason why nuclear fusion and fission are exothermic processes. In order for a particular reaction to take place, there must be sufficient energy so that starting product mass + binding energy + kinetic energy = end product mass + binding energy + kinetic energy. If the starting products do not have sufficient mass and kinetic energy to equal the end products, the reaction cannot occur.

Here is a link better explaining binding energy: http://hyperphysics.phy-astr.gsu.edu...ne/nucbin.html


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