Originally Posted by mathwonk
one does not need any fancy space to get examples. just take the real line and omit say the interval (1,2). then the closure of the open ball of radius 2 about 0 is no longer the closed ball of radius 2 about 0.
|
Because the closed ball of radius 2 includes 2, and the closure of this open ball does not, this closure is not the closed ball of radius 2. However,the closure of the set is,for example, the closed ball of radius 1.5 about -0.5 -- an example of the problem that you described with discrete topologies.
This is essentially the same solution but it resolves that issue.
Consider the a plane, but remove the subset where

. Now, under the usual topology, the open ball of radius 2 about 0 has a closure that is not a closed ball.