| New Reply |
Directional Derivatives and Limits |
Share Thread | Thread Tools |
| Mar31-12, 10:16 AM | #1 |
|
|
Directional Derivatives and Limits
How can I use the directional derivative of a two variable function to show that the limit does not exist? For example, suppose I have a function f(x,y)=g(x)/f(y) and g(a)=f(b)=0 and the limit as x and y go to a and b is 0. How would I use the directional derivative to show that the limit at (a,b) does not exist.
So far, I have tried to take the directional derivatives of the f(x,y) at points around the (a,b), but I feel this is inconclusive because nothing is known about the function itself, other than the fact that it is undefined at (a,b). |
| Mar31-12, 12:17 PM | #2 |
|
|
you can choose different paths, and if the paths aren't equal, the limit does not exist.
|
| Mar31-12, 01:31 PM | #3 |
|
|
|
| Mar31-12, 01:53 PM | #4 |
|
|
Directional Derivatives and Limits
What you have written really does not make much since. You say "f(x,y)=g(x)/f(y)" so that you are using f both for a function of 1 variable and a function of two variables. I think what you intend would be better written "f(x,y)= g(x)/h(y)".
In any case, it is impossible to give an answer to your question without more information as to what f and g are like close to 0. |
| Mar31-12, 02:39 PM | #5 |
|
|
g(y)/(f(x) not g(x)/f(y). As far as providing more information, g(x)/h(y) represents any function that is undefined at a particular point. The only information that is given is that the line x=a is not in the domain, and the answer can be shown with a directional derivative, although any method is acceptable; however, I must show that the limit of f(x,y) at (a,b) does not exist. As far as describing what f(x) and g(y) are like close to 0, I do not know, since f(x) and g(y) merely represent one variable functions, but nothing specific. |
| Mar31-12, 04:39 PM | #6 |
|
|
Try to approach is coming from a direction of the x-axis and of the y-axis. Are these two limits the same?
|
| Mar31-12, 05:08 PM | #7 |
|
|
|
| Mar31-12, 05:57 PM | #8 |
|
|
Could I just simply show that the directional derivative at (a-1,b) in the direction of (a+1,b) is different from the directional derivative at (a-1,b+1) in the direction of (a+1,b+1)?
|
| Mar31-12, 08:20 PM | #9 |
|
|
|
| Mar31-12, 08:32 PM | #10 |
|
|
|
| Apr1-12, 04:25 PM | #11 |
|
|
bump
|
| New Reply |
| Thread Tools | |
Similar Threads for: Directional Derivatives and Limits
|
||||
| Thread | Forum | Replies | ||
| Directional Derivatives | Calculus & Beyond Homework | 7 | ||
| Directional Derivatives vs. Partial Derivatives | Calculus | 10 | ||
| Directional derivatives | Calculus & Beyond Homework | 6 | ||
| estimating partial derivatives/directional derivatives | Calculus & Beyond Homework | 1 | ||
| Directional Derivatives | General Math | 2 | ||