
#1
Apr912, 12:13 PM

P: 6

Hello ,
I am trying to linearize [itex]\dot{x}[/itex]+√x = 0. The only equilibrium point is at x=0; but the derivative is not defined at this point. Does any body have a suggestion? Regards. 



#2
Apr912, 04:41 PM

Mentor
P: 4,499

Why are you trying to linearize it?




#3
Apr912, 05:14 PM

P: 6

hello Office_Shredder
I just got interested in it when talking to a friend about problems that we can encounter 



#4
Apr912, 06:02 PM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,879

Linearization problem
[itex]\sqrt{x}[/itex] cannot be linearized at x= 0 precisely because its derivative does not exist.



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