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Newton's Laws/ Tension Forces Problem |
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| Apr14-12, 06:18 PM | #1 |
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Newton's Laws/ Tension Forces Problem
1. The problem statement, all variables and given/known data
Two Objects are hung from strings. The top object (m1) has a mass of 18 kg and the bottopm object (m2) has a mass of 12 kg. Looks like this: http://www.google.ca/imgres?q=physic...9,r:6,s:0,i:77 (a). Calculate tension in each string. (b) Calculate the tension in each string if you pull down on m1 with a force of 45 N [down] 2. Relevant equations FNet = ma Fg = mg g = 9.8 3. The attempt at a solution I knew how to do (a). I creted a free body diagram for each weight first. Then for m1: FNet = T1 - Fg 0 = T1 - Fg ----> FNet = 0 because it is at rest T1 = Fg T1 = (18)(9.8) T1= 176.4 N And then i did the same for the second one, and came up with T2 = 117.6 Then I got to (b). But im lost. I attemted to find acceleration by doing: FNet = Fa ----> Fa = the 45 N FNet = 45 N ma = 45 N (m1 + m2)a= 45 ---- a= 45/(18 + 12) a = 1.5 So: FNet = T1 - Fg1 (18)(1.5) + (9.8)(18) = T1 T1 = 203.4 N According to my answer key, this is not right. Please help. 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
| Apr14-12, 07:57 PM | #2 |
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Recognitions:
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T1 is supporting BOTH masses so the mass used to calculate T1 should be 30kg. T2 is supporting only M2 so your answer is probably correct. With a free body diagram:- for M2: M2g down, T2 up so your answer should be correct for M1: M1g down + T2 down, T1 up For part b, there is no acceleration; merely an EXTRA 45N down in the free body diagram for M1 |
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| forces, laws, mass, tension. newton's |
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