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Self-Dual Field Strength in complex coordinates |
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| Apr25-12, 05:27 AM | #1 |
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Self-Dual Field Strength in complex coordinates
Hi guys,
I have to brush up my knowledge about self-dual Yang Mills and I'm reading an ancient paper by Yang about it...and of course I'm stuck...although Yang writes 'it is easy to see that'... Ok, so the self-duality condition of the YM field strength tensor is defined as [tex] 2F_{\mu\nu}=\epsilon_{\mu\nu\rho\sigma}F^{\rho\sigma}[/tex]. If I know go to complex coords defined by [tex]\sqrt{2}y=x_1+i x_2 \quad \sqrt{2}\bar{y}=x_1-i x_2[/tex] and [tex]\sqrt{2}z=x_3+i x_3 \quad \sqrt{2}\bar{z}=x_3-i x_4[/tex] the metric transforms to [tex]g_{y\bar{y}}=g_{\bar{y}{y}}=g_{z\bar{z}}=g_{\bar{z}{z}}=1[/tex]. So far i've understood everything. But then Yang says it's easy to see that the self-duality condition becomes [tex]F_{yz}=0=F_{\bar{y}\bar{z}}[/tex] [tex]F_{y\bar{y}}=F_{z\bar{z}}[/tex] The question know is: how do i see the last two equations? Does the epsilon tensor somehow transform if i go to these complex coords? Cheers, earth2 |
| Apr25-12, 10:30 AM | #2 |
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The self-duality condition says F12 = - F34, F13 = F24, F14 = - F23. So for example (ignoring √2's)
Fyz = F13 -i F23 -i F14 - F24 ≡ 0 |
| Apr25-12, 12:24 PM | #3 |
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Ah cool, i didn't know that i could just plug in numbers back :) Nice, thank you!
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