
#1
May412, 04:57 PM

P: 38

P = mv so do this mean that the product of v is μg and the product of m is weight?
So it could be written P = wμg How is this formula derived Vf = √(Vi^2 + (2ad)) 



#2
May412, 05:41 PM

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Hi Probie1!
what is the context (and what do you mean by "product")? 



#3
May412, 06:45 PM

P: 38

Does product not mean... umm the make up... it is part of or makes up?
I guess the context of all this is I am trying to undertand how formula's come about. P = mv so do this mean that the product of v is μg and the product of m is weight? So it could be written P = wμg This is another question. How is this formula derived Vf = √(Vi^2 + (2ad)) 



#4
May412, 07:03 PM

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Is the product of P actually wug and what about
Mathematically "product" means the result of multiplying numbers. It simply doesn't make sense to talk about the "product" of a single number as in "product of v is μg" or "the product of m is weight". Perhaps you mean it the other way weight is the product of mg. That is "mass times the acceleration due to gravity of an object is the force on that object due to gravity" by definition its "weight". I'm not sure what you could mean by "v is the product μg", if that is what you intend, because you have not told us what μ is and it is not a standard symbol. Sometimes μ is used for the "coefficient of drag" but that doesn't make sense here. Assuming g is the acceleration due to gravity and v is velocity, their standard meanings, since v would have units of "meters per second" and g "meters per seconds squared", μ would have to have units of "seconds" it would have to be a "time". Is that correct?




#5
May412, 07:22 PM

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#6
May512, 01:54 AM

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Hi Probie1!
(try using the X^{2} and X_{2} buttons just above the Reply box ) So we start with a = constant. Then, integrating, v = at + v_{i}. And integrating again, d = 1/2 at^{2} + v_{i}t. Can you finish the proof? What did you mean by P m v m and g ? 



#7
May512, 04:53 PM

P: 38

D= at + vi^{2} Alright... stop laughing. m=mass v=velocity g = gravity μ = friction w= weight I thought that if P=mv then v = a = μg but then I remembered where I left my brain because a = change in velocity over a change in time. So it can't possibly be the way I was thinking. So just forget I was so stupid to write that down. 


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