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Dipole moment of a sphere? |
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| May6-12, 02:56 AM | #1 |
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Dipole moment of a sphere?
1. The problem statement, all variables and given/known data
The electric potential of a grounded conducting sphere of radius r in a uniform electric field [tex]E_{0}\hat{k}[/tex]along the z direction is given by [tex]V(r,\theta )=-E_{0}r\cos \theta +\frac{E_{0}R^{3}\cos \theta }{r^{2}}[/tex] where r is the distance from the centre of the sphere and θ is the angle the radius vector makes with the z axis. (a)what is the dipole moment acqured by the sphere? 2. Relevant equations 3. The attempt at a solution Surface charge density, [tex]\sigma (\theta )=-\varepsilon \frac{\partial V}{\partial r}% |_{r=R}=3\varepsilon E_{0}\cos \theta [/tex] Dipole moment, [tex]P=\int \sigma (\theta ^{\prime })r^{\prime }ds^{\prime } =\int_{0}^{\pi }3\varepsilon E_{0}\cos \theta ^{\prime }r^{\prime }r^{\prime 2}\sin \theta ^{\prime }d\theta ^{\prime }d\phi ^{\prime } =6\pi \varepsilon E_{0}R^{3}\int_{0}^{\pi }\cos \theta ^{\prime }\sin \theta ^{\prime }d\theta ^{\prime } =6\pi \varepsilon E_{0}R^{3}\int_{-1}^{1}\cos \theta ^{\prime }d(\cos \theta ) =6\pi \varepsilon E_{0}R^{3}[/tex] But this donot match with the real answer. :( |
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