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Quantum physics problem: SE and operators |
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| Jun29-12, 12:04 AM | #1 |
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Quantum physics problem: SE and operators
Hello.
I have this problem at hand: 1. The problem statement, all variables and given/known data A quantum mechanical system has a hamilton operator [itex]\hat{H}[/itex] and another, time independent operator [itex]\hat{A}_{0}[/itex]. Construct a time dependent operator [itex]\hat{A}(t)[/itex] so that: <ψ(t)|[itex]\hat{A}_{0}[/itex]|ψ(t)> = <ψ(0)|[itex]\hat{A}(t)[/itex]|ψ(0)> for all states ψ(t) that develop in time according to the SE. 3. The attempt at a solution In the derivation of the Schrödinger equation, we use the unitary operator [itex]\hat{U}(t)[/itex] to calculate the effect of time on the state ψ(0)... So ψ(t) = [itex]\hat{U}(t)[/itex] ψ(0) = exp(-i/[itex]\hbar \hat{H}[/itex] t) ψ(0). In other words: <ψ(t)|[itex]\hat{A}_{0}[/itex]|ψ(t)> = <[itex]\hat{U}(t)[/itex] ψ(0)|[itex]\hat{A}_{0}[/itex]|[itex]\hat{U}(t)[/itex] ψ(0)> =<ψ(0) |[itex]\hat{U}(t)^{+} \hat{A}_{0} \hat{U}(t)[/itex] | ψ(0)>. so my "solution" is that [itex]\hat{A}(t)[/itex] = [itex]\hat{U}(t)^{+} \hat{A}_{0} \hat{U}(t)[/itex]... But this is way too simple to be correct... So what am I missing? Thanks /D |
| Jun29-12, 03:09 AM | #2 |
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Mentor
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Looks fine to me. I suppose you could write explicitly what ##U(t)^\dagger## is equal to.
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| Jun29-12, 07:53 AM | #3 |
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It's correct, and what you have done is actually to find the correspondence between the Schrödinger and the Heisenberg picture. See e.g.
http://en.wikipedia.org/wiki/Heisenberg_picture http://en.wikipedia.org/wiki/Schrödinger_picture |
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| operators, quantum, schrödinger equation |
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