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How is molecular hydrogen detected?
 Quote by Bobbywhy
Now I am a trained listener and a professional public speaker (Toastmasters International=28 years) but, unfortunately, I never could figure out what message you were trying to communicate in each of those four modules. Perhaps your written script could be revised to be more coherent and to clearly address the point you want to make. The point is I couldn't find the point.
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I have made three more modules. Hopefully you will find these more coherent.
Secondary Explosion Explanation. In this module, I discuss why is it that I am multiplying 1 mile per hour times the age of the universe.
Reductio Ad Absurdam vs. Strawman: In this module I discuss the reasons why a kinematic model of the universe has been rejected. From what I have seen, they are all based on straw-man arguments posing as ruductio-ad-absurdam.
If I'm right, What do we have to "throw away" about what we know about gravity?: In this module, I discuss the particular reasonong which was addressed earlier in posts 45, 47, and 48, 53, 56, 54, in this thread. For your convenience, I am re-posting all the relevant parts of that argument below. You will notice that post 56 and 54 have been reversed, chronologically, in the tradition of the dialectic--in post 56 I had posted a hypothesis, that distant forces were observer dependent, and then later realized that twofishquant had already posted the contradiction to this hypothesis--that indeed the distant forces could, with bookkeeping, be found to be the same.
 Quote by JDoolin
Do you have some other reasoning, perhaps based on an application of Gauss's Law? I'm asking that because I'm pretty sure that I've seen such an argument made by none other than Einstein himself. However, I don't remember where I saw it; some book I've long since returned to the library (in frustration).
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 Quote by twofish-quant
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 Quote by JDoolin
Ah, yes, thank you for that article. This was exactly the argument that I was thinking of. I've seen this argument in books, but I had never found it online. I was calling it "Gauss Law" but it is "Birkhoff's Theorem."
While I am essentially in agreement with Birkhoff's theorem, the article you reference is making a major error in its application, (and if I am not mistaken, Einstein made this same mistake, and was perhaps its originator.) If you are calculating the forces on particles A, B, C, and D, it is completely inappropriate for you to draw a circle around an arbitrary observer O, and then treat all of the mass in that circle as though it were a point mass at point O.
It would make much more sense to account for the masses near the objects A, B, C, D, respectively, to calculate the forces that are acting upon them.
(The other major error in the article is equation 2.3... Failure to apply time dilation and the relativity of simultaneity.)
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 Quote by twofish-quant
Here's another way of thinking of it.....
I have point A. You can argue that all of the forces are balanced at point A, so it doesn't accelerate.
I have point B. You can argue that all of the forces are balanced at point B, so it doesn't accelerate.
AHA!!! You say, the universe must then be non-accelerating!!!!
But that doesn't work. If I start with point A as my origin, and then look at point B, I find that there is a force at point B pulling it toward point A. But wait, I just showed that the forces are balanced if I take point B as the origin? What gives?
The issue here is that the forces at point B when viewed from point A are *different* from the forces at point B when viewed from point B, because when you change coordinate systems then the forces change. But how can that be? Don't forces stay the same when you change between inertial coordinate systems?
Yes, but from point A's point of view, point B is not an inertial coordinate system, it's accelerating, and because it's accelerating, when you switch between point A and point B, the forces change. From point B's point of view, it's an inertial coordinate system, and A is accelerating. So when you switch between A and B, you have to change the forces to take into account the fact that the coordinate systems are non-inertial.
From A's point of view, there is a force on B pulling B toward A, and there is zero forces at A. Now when you switch to B's point of view, you are a non-inertial reference frame from A's point of view. To make it inertial, you have to subtract the forces that are acting on it. That causes the forces at B from B's point of view to go to zero, and then causes the A to go from zero force to the opposite of what was the force that A sees acting on B.
So if you take any point as the origin, you will see a force of zero for that point, but you will see non-zero forces for points other than the origin.
Now then you see how the universe works. We don't have any infinite clouds, but we have clouds that are "practically" infinite. You take something like the interstellar medium with a one light year cube, and then take a piece that is much, much smaller, and see how you calculate gravity.
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 Quote by JDoolin
Thank you for giving further explanation here.
I still think that ignoring the relativity of simultaneity is a flaw, but I also realize now that I was misunderstanding Einstein's argument.
He was literally saying that the force on a distant particle is an observer dependent quantity, while time is an observer independent quantity. That seems amazing to me, and I will have to think about it further.
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 Quote by twofish-quant
And if you do your bookkeeping right, you come up with the same answer. The important thing is to keep track of what reference frame you are in so that you can account for non-inertial effects correctly.
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I meant to ask, precisely what bookkeeping is done, so that you all get the same non-zero answer? I can agree that with correct bookkeeping, you should get the same answer, but by my calculation that answer should be zero. Because I don't believe that "correct bookkeeping" is represented by drawing a circle extending out to the radius of the object and stopping (as is done on page 2-3 here: http://www.ast.cam.ac.uk/~pettini/Ph.../lecture02.pdf) . I think the circle needs to be drawn to encompass a large volume around the object. At least, make the circle large enough to encompass the masses that are in the object's immediate vicinity.
With this sort of bookkeeping, all observers would, indeed, agree that the force on the object would be the same. But the "same value" that everyone would come up with, would be zero.
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