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Merry-go-round with brick and sliding friction. |
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| Jul20-12, 08:34 PM | #1 |
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Merry-go-round with brick and sliding friction.
1. The problem statement, all variables and given/known data
The picture shows a rotating platform that serves as a playground merry go round. The platform rotates on low-friction bearings about its center axis. It has a radius of 2.0 meters, and its moment of inertia about the center axis is 200 kg m2. Suppose that the platform is given an initial rotation rate of 1.0 radians per second. A small dense brick having a mass of 50 kg, initially at rest, is then placed on the platform at a distance of 0.5 meters from the rotation axis. The brick initially slides, but eventually stops sliding at a distance 1.0 m from the axis. How many Joules of mechanical energy are converted to heat? 2. Relevant equations [itex]I_{brick}=mr^{2}[/itex] [itex]L_{i}=L_{f}=>I_{i}\omega_{i}=I_{f}\omega_{f}[/itex] (cons. of angular momentum) [itex]ΔK=-fx +W_{ext}[/itex] (work-energy theorem) 3. The attempt at a solution [itex]I_{brick i}=(50kg)(0.25m^{2})=12.5kg.m^{2}[/itex] [itex]I_{brick f}=(50kg)(1m^{2})=50kg.m^{2}[/itex] [itex]I_{i}=I_{disk i}+I_{brick i}=212.5kg.m^{2}[/itex] [itex]I_{f}=I_{disk f}+I_{brick f}=250kg.m^{2}[/itex] [itex]\omega_{f}=\frac{I_{i}}{I_{f}}\omega_{i}=0.85\frac{rad}{s}[/itex] [itex]ΔK=-fx[/itex] (no external work, just friction) [itex]\frac{1}{2}I_{i}\omega_{i}^{2}-\frac{1}{2}I_{f}\omega_{f}^{2}=15.94 J[/itex] Just wondering if my solution method is looking ok. Thanks for the help! |
| Jul20-12, 10:17 PM | #2 |
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