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Stokes theorem in a cylindrical co-ordinates, vector field |
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| Aug19-12, 12:35 AM | #1 |
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Stokes theorem in a cylindrical co-ordinates, vector field
1. The problem statement, all variables and given/known data
given a vector field [B]v[/B=]Kθ/s θ (which is a two dimensional vector field in the direction of the angle, θ with a distance s from the origin) find the curl of the field and verify stokes theorem applies to this field, using a circle of radius R around the origin 2. Relevant equations Stokes Theorem is: [itex]\int[/itex]∇×v.da=[itex]\oint[/itex]v . dl and the curl in cylindrical co-ordinates is: 1/s (∂vz/∂θ-∂vθ/∂z) s+(∂vs/∂z-∂vz/∂s) θ+1/s(∂/∂s (s vθ)-∂vs/∂θ) z Where vz=0; vs=0; vθ=kθ/s 3. The attempt at a solution IN cylindrical co-ords; dl=ds s +s dθ θ+dz z The line integral is hence equal to ∫kθdθ with θ runing from 0 to 2[itex]\pi[/itex] Which has a solution of 2k [itex]\pi[/itex]2 However, the curl is zero except for at the centre, where 1/s goes to infinity; so the integral on the other side has a delta function, and the integral will come out at 2k[itex]\pi[/itex] 2meaning the integral will be something like: ∫∫∂(s)kθdθds which evaluates to 2k [itex]\pi[/itex]2 as required; But I'm not sure how to get that integral... |
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